19392 = 2 x 2 x 2 x 2 x 2 x 2 x 3 x 101;
43008 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 3 x 7
HCF = 26 x 3 = 192
19409 / 192 = 101 rem 17
43037 / 192 = 224 rem 29
138. What is required is the largest number n such that: 285 = jn + 9 1249 = kn + 7 So subtract the required remainders and then find the hcf of the results: 285 - 9 = 276 1249 - 7 = 1242 Find hcf of 276 and 1242: 1242 / 276 = 4 r 138 276 / 138 = 2 r 0 hcf of 276 and 1242 is 138. Thus 138 is the largest number to divide 285 with a remainder of 9 and divides 1249 with a remainder of 7.
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105 can be divided evenly by 1, 3, 5, 7, 15, 21, 35, and 105. These are all the factors of 105, meaning they divide into 105 without leaving a remainder. Additionally, 105 can be divided by other numbers that are not factors, but those divisions will result in remainders.
1
It is 1 because it is the highest number that will divide evenly into both numbers leaving no remainders
Factors are whole numbers that will divide into other whole numbers leaving no remainders
It is 12 because 12 is the highest common factor of both number that will divide into them evenly and leaving no remainders.
The greatest remainder when you divide by 21 is 20. This is because the remainder is always less than the divisor. Therefore, when a number is divided by 21, the possible remainders range from 0 to 20, with 20 being the highest.
The GCF of both numbers is 2 because it is the biggest number that will divide evenly into both numbers leaving no remainders.
5
0.5
Oh, dude, the greatest common factor of 90, 126, and 252 is 18. It's like the coolest number that can divide all three of those numbers without leaving any remainders. So, yeah, 18 is the boss in this math party.
2, 1 or 0.
4
138. What is required is the largest number n such that: 285 = jn + 9 1249 = kn + 7 So subtract the required remainders and then find the hcf of the results: 285 - 9 = 276 1249 - 7 = 1242 Find hcf of 276 and 1242: 1242 / 276 = 4 r 138 276 / 138 = 2 r 0 hcf of 276 and 1242 is 138. Thus 138 is the largest number to divide 285 with a remainder of 9 and divides 1249 with a remainder of 7.
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