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19392 = 2 x 2 x 2 x 2 x 2 x 2 x 3 x 101;

43008 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 3 x 7

HCF = 26 x 3 = 192

19409 / 192 = 101 rem 17

43037 / 192 = 224 rem 29

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Q: Find the greatest number that will divide 19409 and 43037 leaving remainders 17 and 29 respectively?
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