There's no way to say anything about that quantity
until you know what numbers 'a' and 'b' are.
(That phrase is used in the discussion of mix-products generated in incidental
diodes and non-linearities internal to the waveguide branching network of a
multi-channel microwave terminal, but I'm sure you didn't mean it that way.)
2a
2a+6b
Let's solve this equation together, friend. To isolate b, we can start by subtracting 2a from both sides of the equation. This will leave us with b equals P minus 2a. Remember, there are many ways to approach a problem, and it's all about finding the one that works best for you.
a-^2a-b^-a-b
since a=1a, 3a-1a=2a
2a
2a+6b
(a - 2b)(2a - b)
x equals negative b plus or minus the square root of b squared minus 4bc over 2a
Use (-b + or - sqrt(b^2-4ac))/(2a) A is 10 B is -9 C is -6
2a-5
2a - a = a
Let's solve this equation together, friend. To isolate b, we can start by subtracting 2a from both sides of the equation. This will leave us with b equals P minus 2a. Remember, there are many ways to approach a problem, and it's all about finding the one that works best for you.
2a+5
The quadric equation is: negative b plus or minus the square root of b squared minus 4ac all over(divided by) 2a
a-^2a-b^-a-b
When simplified it is: 2a+8b+4