Use (-b + or - sqrt(b^2-4ac))/(2a)
A is 10
B is -9
C is -6
9x2-9x-10 = (3x+2)(3x-5) when factored
With the help of the quadratic equation formula
(9x + 8)(9x - 8)
x = -2/3,7/6
2x2-9x+4 = (2x-1)(x-4) when factored
9x2-9x-10 = (3x+2)(3x-5) when factored
x2 + 9x2 = 10x2
x2-9x can be factored by taking x out of each term x(x-9)
"10x - x" is basically 10 x's minus one x. The answer is 10 minus 1, but in terms of x. Since 10 minus 1 is 9, the answer is 9x.
9x squared plus 16 = 0 factored is plus and minus 4/3 i.
9x^(2) + 16 DOES NOT factor. Remember ; two squared terms with a plus(+) between them DOES NOT factor However, two squared terms with a minus(-) between them DOES factor . Hence 9x^(2) + 16 = (3x)^2) + 4^(2) does NOT factor However, 9x^(2) - 16 = (3x)^2) - 4^(2) does factor to ( (3x - 4)(3x + 4) Note the two different signs.
5x2 + 9x + 13 has no real factors.
With the help of the quadratic equation formula
10x = 9x -25 10x -9x = -25 x = -25
That factors to 3x(3x - 1)
(9x + 8)(9x - 8)
x = -2/3,7/6