* 99
1 x 33, 3 x 11, 11 x 3, 33 x 1
x + 2x = 33 3x = 33 3x/3 = 33/3 x = 11
33 = 3 x 11 54 = 2 x 3 x 3 x 3 GCF = 3
63 = (2x3)3 = 23 x 33 36 = 33+3 = 33 x 33 As 2 ≠ 3 then 23 ≠ 33 ⇒ 63 = 23 x 33 ≠ 33 x 33 = 36 ⇒ 63 ≠ 36
3x = 33 Therefore, x = 33/3 x = 11
1 x 33, 3 x 11 = 33
1 x 33, 3 x 11 = 33
1 x 33, 3 x 11.
1 x 33, 3 x 11
48 = 24 x 3 33 = 3 x 11
The prime factors are: 2 x 3 x 3 x 3 OR (2 x 33)
You look for two integers which multiply to 33 and whose sum is 14 and these happen to be 11 and 3. So x^2 - 14x + 33 = x^2 - 3x - 11x + 33 =(x^2 - 3x) - (11x - 33) [sign for 33 changes because the bracket has a minus sign] =x * (x-3) + 11 * (x-3) =(x - 3) * (x - 11)