0
3x^0 = 3(x^0) = 3 (3x)^0 = 1
4
3
(4x ^2 + 3) + (3x ^2 + 8) = ( 4x^2 + 3x^2 ) + (3+8) = 7x^2 + 11
4x to the 3rd power -4x to the 2nd power -43 when x=3
The integral of 3x is ln(3)*3x. Take the natural log of the base and multiply it by the base raised to the power.
It is -21x + 7
No, 9x - 3x is not 6, nor is it 6x. There is no simple one-term answer. The best that can be done is that it is 3x*(3x - 1).
3x^2 - 27 = = 3(x^2 - 9) = 3(x^2 - 3^2) = 3(x - 3)(x + 3)
3x = 2y + 3 3x -3 = 2y +3 -3 3x - 3 = 2y (3x -3)/2 = 2y / 2 y = 1/2 x (3x - 3) 3x = 2y +3 3x - 3x = -3x +2y +3 0 = -3x +2y +3 -1 x (0) = -1 x (-3x +2y +3) 0 = 3x - 2y -3
3x = 2y + 3 3x -3 = 2y +3 -3 3x - 3 = 2y (3x -3)/2 = 2y / 2 y = 1/2 x (3x - 3) 3x = 2y +3 3x - 3x = -3x +2y +3 0 = -3x +2y +3 -1 x (0) = -1 x (-3x +2y +3) 0 = 3x - 2y -3
it is no power if it was a power it would have a small 3 at the top of the right side of the x..