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The factor pairs of 500 are 1 x 500, 2 x 250, 4 x 125, 5 x 100, 10 x 50, and 20 x 25
Here you go --500 x 500 = 250,000 (5x5 + 4 zeros)250,000 x 500 = 125,000,000 (25x5 + 4+2= 6 zeros)
9000 x 500 = 4,500,000.Think of it as 9 x 5 (=45) with 3 zeros (from the 9000) and 2 more zeros (from the 500) written after it.
500 x 2 = 1000 NB its just tha same as saying 5 x 2 = 10 , but you 'stick' couple of extra zeroes on.
There's a trick to this one. Let 1 + 2 + ... + 500 be the sum of all integers 1 to 500, called X Now, imagine we want to add the sum the integers from 1 to 500 and to the sum of the integers from 1 to 500. This would give us 2*X we can write it as 1 + 2 + ... + 500 + 1 + 2 + ... + 500 But that's not particularly useful. What if we look at it as: 1 + 2 + ... + 499 + 500 + 500 + 499 + ... + 2 + 1 adding the numbers that are directly on top of each other, we get 500 + 1 = 501, 499 + 2 = 501... 1 + 500 = 501 Thus every term is 501, and we have 500 terms. So, we have 501*500 = 2X Thus X, the sum from 1 to 500, is (500*501)/2 = 125,250