65.
13 remainder 5
70/13 = 5 remiander 5
13x2x5=130
To determine how many times 5 can go into 68, you would perform division. 68 divided by 5 equals 13 with a remainder of 3. This means that 5 can go into 68 evenly 13 times, with a remainder of 3.
To determine how many times 5 can go into 65, you would perform division. 65 divided by 5 equals 13, so 5 can go into 65 thirteen times without any remainder. This is because 5 multiplied by 13 equals 65.
5 times 13 times 2 = 2 times 5 times 13 = 10 times 13 = 130
5 goes into 13 two times with 3 left over.
The product is: 13 times 5 = 65
10over 5
13 remainder 5
To determine the number of different 5-card hands that can be dealt from a deck of 13 cards, you can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ), where ( n ) is the total number of cards, and ( k ) is the number of cards to choose. In this case, ( n = 13 ) and ( k = 5 ). Calculating this gives: [ C(13, 5) = \frac{13!}{5!(13-5)!} = \frac{13!}{5! \times 8!} = \frac{13 \times 12 \times 11 \times 10 \times 9}{5 \times 4 \times 3 \times 2 \times 1} = 1287. ] Thus, there are 1,287 different 5-card hands that can be dealt from a deck of 13 cards.
13/100
2 times 2 times 5 times 5 times 11 times 13.
13√10
5 times with a remainder of 5
The 13 times tables are as follows: 1 times 13 is 13, 2 times 13 is 26, 3 times 13 is 39, 4 times 13 is 52, 5 times 13 is 65, 6 times 13 is 78, 7 times 13 is 91, 8 times 13 is 104, 9 times 13 is 117, 10 times 13 is 130, 11 times 13 is 143, and 12 times 13 is 156.
13 times