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It is 5/3*a - 2/3
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7a plus 4 equals 5a plus 7?
7a + 4 = 5a + 7 7a = 5a + 3 2a = 3 a = 3/2
3a plus 5 equals 5a plus 3?
If 3a+5=5a+3, then: 3a+5 - 3a = 5a+3 - 3a 5=2a+3 5 - 3=2a+3 - 3 2=2a a=1
What is 5a x 5a?
5a times 5a would equal 25a^2.
How do you find five consecutive number whose sum is 465?
Let the number be represented by 'a' a+(a+1)+(a+2)+(a+3)+(a+4)=465 a+a+1+a+2+a+3+a+4=465 a+a+a+a+a+1+2+3+4=465 5a+10=465 5a=465-10 5a=455 5a/5=455/5 a=91 So if a=91 a+1=92 a+2=93 a+3=94 a+4=95
How do you factorise 10a-5ab?
15
What is 5a plus 3 plus 2a-2 plus a?
5a + 3 + (2a - 2) + a= 5a + 3 + 2a - 2 + a= 8a + 1
7a plus 4 equals 5a plus 7?
7a + 4 = 5a + 7 7a = 5a + 3 2a = 3 a = 3/2
How do you solve a squared minus 4 over 2 plus 6a times 3 plus 9a over a squared plus 5a plus 6?
In order to solve something, there needs to be an equation. If I have read your equation right you have: (a² - 4)/(2 + 6a) x (3 + 9a)/(a² + 5a + 6) This looks like it needs to be simplified. There are two fractions being multiplied, so multiply the numerators and denominators together, giving: (a² - 4)/(2 + 6a) x (3 + 9a)/(a² + 5a + 6) = ((a² - 4)(3 + 9a)) / ((2 + 6a)(a² + 5a + 6)) Now, simplify the polynomials to remove the squared terms and any common factors: a² - 4 = (a - 2)(a + 2) 2 + 6a = 2(1 + 3a) 3 + 9a = 3(1 + 3a) a² + 5a + 6 = (a + 3)(a + 2) Giving: ((a² - 4)(3 + 9a)) / ((2 + 6a)(a² + 5a + 6)) = ((a + 2)(a - 2)3((1 + 3a))/(2(1 + 3a)(a + 3)(a + 2)) This can now be simplified by cancelling out equivalent terms, giving: ((a + 2)(a - 2)3(1 + 3a))/(2(1 + 3a)(a + 3)(a + 2)) = ((a - 2)3) / (2(a+3)) = 3(a - 2) / 2(a + 3) = (3a - 6) / (2a + 6)
How do you factor 3a2-16a plus 5?
3a2 - 16a + 5 = 3a2 - 15a - a + 5 = 3a(a -5) - 1(a -5) = (3a - 1)(a - 5)
3a plus 5 equals 5a plus 3?
If 3a+5=5a+3, then: 3a+5 - 3a = 5a+3 - 3a 5=2a+3 5 - 3=2a+3 - 3 2=2a a=1
Cuánto es 5a x 5a?
(5a)^2 or a^2+10a+25
What is the value of a in 13a - 6 plus a equals 5a plus 3 plus 3a?
13a - 6 + a = 5a + 3 + 3a 13a + a - 5a - 3a = 3 + 6 6a = 9 6a/6 = 9/6 a = 3/2
What is 5a x 5a?
5a times 5a would equal 25a^2.
What is the answer of 25a exponent of 5 15a exponent of 4-35a exponent of 3-40a exponent of 3 10a divided by 5a?
The answer to the expression 25a^5 + 15a^4 - 35a^3 - 40a^3 + 10a divided by 5a is 5a^4 + 3a^3 - 7a^2 - 8a + 2.
How do you find five consecutive number whose sum is 465?
Let the number be represented by 'a' a+(a+1)+(a+2)+(a+3)+(a+4)=465 a+a+1+a+2+a+3+a+4=465 a+a+a+a+a+1+2+3+4=465 5a+10=465 5a=465-10 5a=455 5a/5=455/5 a=91 So if a=91 a+1=92 a+2=93 a+3=94 a+4=95
What is 5a- 2a?
5a- 2a = 3
What is five times the sum of some number plus 3 is equal to 7 times the number minus 1?
5a + 3 = 7a - 1 add 1 to both sides 5a + 4 = 7a so 4 = 2a as 5a + 2a = 7a 4 = 2a = 2 x 2 so a = 2 Check: then 5a + 3 = 10 + 3 = 13 and 7a - 1 = 14 - 1 = 13
