x - 7 = 8
x = 7 + 8
x = 15
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This is the product of 8 times 7. And that's 8 * 7 = 56, not 57.
I can prove that it's 56. 8 * 8 = 64, which is the number 8 eight times. So 8 * 7 = the number 8 but only seven times. One less 8 than the 64 problem. So 8 * 7 = 8 * (8 - 1) = 64 - 8 = 56 QED.
8 times 7 is 56. You have to add 8, 7 times (8+8+8+8+8+8+8) or add 7, 8 times (7+7+7+7+7+7+7+7)
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8 x 7 = 56
7 x 8 = 56
Answer 56
8 × 7 = 65 bestie 💚
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57
x+8=-4
If digits can't be repeated, then there are (7 x 7 x 6 x 5 x 4 x 3 x 2) = 35,280If digits can be repeated, then there are (7 x 8 x 8 x 8 x 8 x 8 x 8) = 1,835,008
short answer -1 and -7 long worked answer let x = one of the integers let y = the other integer x+y = -8 xy = 7 solve for y y = -8 - x plug y in x(-8 - x) = 7 rearrange -x^2 - 8x - 7 = 0 divide both sides by -1 x^2 + 8x + 7 = 0 factor (x + 7)(x + 1) = 0 x = -1, -7 y = -8 - x so y = -8 + 1 = -7 or -8 + 7 = -1 so when x = -1, y = -7 when x = -7, y = -1
-2 x -4 x -7 x -8 = 448
7 x 8 = 56