-2 x -4 x -7 x -8 = 448
4*4 = 16 (4+4 = 8)3*5 = 15 (3+5 = 8)2*6 = 12 (2+6 = 8)1*7 = 7 (1+7 = 8)0*8 = 0 (0+8 = 8)So 4 and 4 produce the largest product and still have the sum of 8.Assumptions:only integers,that this can be extrapolated (-1*9 < 0*8 etc)
10 combinations- 4&7, 4&0, 4&8, 4&2, 7&0, 7&8, 7&2, 0&8, 0&2, and 8&2
4/7*56 = 4*56/7 = 4*8 = 32
1/2 of 13/4= 1/2 of 7/4 = 7/8 cups.1/2 of 13/4= 1/2 of 7/4 = 7/8 cups.1/2 of 13/4= 1/2 of 7/4 = 7/8 cups.1/2 of 13/4= 1/2 of 7/4 = 7/8 cups.
The four consecutive even integers are 4, 6, 8, 10. The product of 8 and 10 is 80. Algebraically, the equation to find the four integers is : [x + (x+2) + (x+4) + (x+ 6)]/4 = 7 (4x + 12) / 4 = 7 x + 3 = 7 x = 4 x+2 = 6 // x+4 = 8 // x+6 = 10
4*4 = 16 (4+4 = 8)3*5 = 15 (3+5 = 8)2*6 = 12 (2+6 = 8)1*7 = 7 (1+7 = 8)0*8 = 0 (0+8 = 8)So 4 and 4 produce the largest product and still have the sum of 8.Assumptions:only integers,that this can be extrapolated (-1*9 < 0*8 etc)
Yes, here are most of them: (2 * 4) / 8 + 6 = 7 (2 - 6) / 4 + 8 = 7 (2 / 8) * 4 + 6 = 7 (4 - 6) / 2 + 8 = 7 (4 / 8) * 2 + 6 = 7 (6 / 2) - 4 + 8 = 7 ((6 + 8) * 2) / 4 = 7 (8 / 2) / 4 + 6 = 7
2(24 + 7) = (2 x 24) + 2 x 7) = 2 x 31 = 62
10 combinations- 4&7, 4&0, 4&8, 4&2, 7&0, 7&8, 7&2, 0&8, 0&2, and 8&2
4/7*56 = 4*56/7 = 4*8 = 32
8
1/2 of 13/4= 1/2 of 7/4 = 7/8 cups.1/2 of 13/4= 1/2 of 7/4 = 7/8 cups.1/2 of 13/4= 1/2 of 7/4 = 7/8 cups.1/2 of 13/4= 1/2 of 7/4 = 7/8 cups.
2 8/7 divided by 4/7 is the same as 8/7 times 7/4... The 7s then cancel out and you get 8/4 which is 2
4/7 * 2/3 = 8/21.4/7 * 2/3 = 8/21.4/7 * 2/3 = 8/21.4/7 * 2/3 = 8/21.
Double 4 x 7 to find 8 x 7.
If that's 1 and 7/8, make it 15/8 x 4/5 = 3/2
4/7 * 7/8 = 4/8 = 1/2.