(b-c)(a+b)-ac
he made the theorem C squared = A squared + B squared and A squared = C squared - B squared or B squared = C squared - A squared
By factoring I get x-3 divided by x+3
Your question can mean one of two things: a) -(2)2 = -4 b) (-2)2 = 4
if you mean a right triangle then the formula is a squared + b squared = c squared. a and b are the legs and c is the hypotunese. the legs are the smallest number then the hypotenese. An example is a=3 , b= ? and c =5 use the formula : a squared + b squared = c squared 3 squared + b squared = 5 squared 9 + b squared = 25 -9 - 9 _________________________________________ b squared = 16 Then you have to take the squared root of 16 which is 4 and 4 is b squared.
No, unless "a" happens to be equal to 0, or to 1.
All the time
hello
(b-4) squared
B squared equals c squared minus a squared then to find B take the square root of you answer for b squared
(b-c)(a+b)-ac
It is: (B -10)(B +10) when factored
To evaluate it you need to know both b and a. But it is possible to factorise it as follows: b2-a2 = (b-a)*(b+a)
It simplifies to 5a+4 !
(b + 8)(b - 1)
(a - 2b)(2a - b)
If your Problem is organized like this: A x squared plus B x plus C, the equation is: (B plus or minus the square root of(B squared minus 4 A C)) over 2A