No, unless "a" happens to be equal to 0, or to 1.
All the time
hello
(b-4) squared
To evaluate it you need to know both b and a. But it is possible to factorise it as follows: b2-a2 = (b-a)*(b+a)
b^3 - 25b^2 - 4b + 100 = 0 b = 25 or b = -2
No, unless "a" happens to be equal to 0, or to 1.
All the time
hello
(b-4) squared
B squared equals c squared minus a squared then to find B take the square root of you answer for b squared
(b-c)(a+b)-ac
To evaluate it you need to know both b and a. But it is possible to factorise it as follows: b2-a2 = (b-a)*(b+a)
An algebraic expression
It simplifies to 5a+4 !
If: b2 = 100 Then: b = 10
Oh, dude, that's just the difference of squares formula! It's like A squared minus B squared equals (A + B)(A - B). So, yeah, you just gotta remember that little math nugget next time you're trying to impress someone at a party or something.