1 half base times height 1/2 (B * h)
Base times vertical height = b x h (same as rectangle).
2(b+h)
27 Bones in the Human Hand
1/3 b x h b=area of base h=height of pyramid
(b+h)(b+h)= b2+2hb+h2.
b times h times 1/2 or b times h divide by 2
A = h/2*(a + b) So 2A/h = a + b and therefore, a = 2A/h - b
no sorry i meant if a times b is 24 and yes it is.
A=b*h area = base (times) height P=2b + 2h perimeter = 2 (times) base (plus) 2 ( times) height A= b*h 12 = b*h 12/b = h let x = b h = 12/x since x = b and h = 12/x therefore P = 2x + 2(12/x)
Which of the following formulas is used to find the area of a trapezoid? Solution: 1/2 h(B+b) The area of a trapezoid is 1/2 times the height times the sum of both bases. h is the height, b is the top base and B is the bottom base. A trapezoid=1/2×h×(B+b)
A = (B x h)/2 As h is four times longer than B, we get h = 4 x B Then A = (B x 4B)/2 = (4 x B2)/2 = 2 x B2 thus B=sqrt(A/2) and h=4 x B=4 sqrt(A/2)
V = 1/3*B*h where B is the base area.
Since the area is (length of base)*(height)/2 {call these dimensions B & H) A1 = B*H/2 With dimensions doubled, A2 = (2*B)*(2*H)/2 = 4*B*H/2 = 4*A1. By not simplifying to 2*B*H, it's easier to see that it is four times the original area. It is 4 times because the two length dimensions are multiplied, and 2 * 2 = 4.
Because the area of a parallelogram is base times perpendicular height
the distance from A to B is 24Km
1/2*b*h one half times base times height