To determine the smallest number of coins that will total exactly 17.85, we need to consider the denominations of the coins available. If we have coins in denominations of 0.01, 0.05, 0.10, 0.25, 1.00, and 2.00, we can use a combination of these coins to reach 17.85. The smallest number of coins needed would be achieved by using the highest denomination coins first, followed by the smaller denominations to make up the difference. The specific combination of coins would depend on the availability of each denomination and the constraints of the problem.
dimes : all coins = 6 : 12+6+18 = 6 : 36 = 1×6 : 6×6 = 1 : 6 Dimes are ⅙ of all coins.
This is only possible if you allow adding coinsNumber of coins in row x Number of rows = total number of coins5 x 2 = 10 coins4 x 4 = 20 coinsYou would need 10 more coins
Let's represent the number of nickels as (x) and the number of quarters as (y). We can create a system of equations to solve for (x) and (y): (x + y = 40) (total number of coins) (0.05x + 0.25y = 8.80) (total value of the coins) From the first equation, we can rewrite it as (x = 40 - y). Substituting this into the second equation gives us (0.05(40 - y) + 0.25y = 8.80). Solving this equation will give us the values of (x) (nickels) and (y) (quarters).
8 of them.
If all coins were dimes he would have $1.30. Every quarter that replaces a dime increases the total by 15c. The total has to be increased by $1.20 which is 15c x 8. He has 8 quarters and 5 dimes.
To determine the smallest number of coins needed for a specific amount of money, we typically consider the denominations available. For example, using coins of higher denominations first can minimize the total number of coins required. The exact number will depend on the total amount and the denominations in question, such as pennies, nickels, dimes, and quarters. If you provide a specific amount and the denominations available, I can give a more precise answer.
It depends on the currency.Current US coins are limited to $1 so the number of coins to reach $19.95 will be 24. Nineteen $1 coins, three quarters and two dimes.In times gone by, US currency included $10 and $5 coins so the number was once lower than the current 24 coins.UK currency has a £2 coin so £19.95 will require 14 coins. Nine £2 coins, one £1 coin, one 50 pence, two 20 pence coins and a 5 pence coin.
A lot
Let ( q ) be the number of quarters and ( d ) be the number of dimes. We have two equations based on the problem: ( q + d = 102 ) (the total number of coins) ( 25q + 10d = 1710 ) (the total value in cents) Solving these equations, we find that there are 6 quarters and 96 dimes.
A multiple of 11 can't be a prime number.
One
The smallest is 55.
20 - 10 of each
You have provided insufficient information to answer the question. You would need to tell either (i) the total number of coins or (ii) the exact total value.
Let the number of ₹1 coins be ( x ) and the number of ₹2 coins be ( y ). We have two equations based on the problem: ( x + y = 50 ) (total coins) and ( x + 2y = 70 ) (total value). Solving these equations, we find ( x = 20 ) and ( y = 30 ). Therefore, the lady has 20 ₹1 coins and 30 ₹2 coins.
Yes, you can make 25 cents with 20 coins. For example, you can use 15 nickels (5 cents each) and 5 pennies (1 cent each) to achieve this total. This combination gives you exactly 25 cents with a total of 20 coins.
If n is the number of nickels and d the number of dimes, then the equations are:n + d = 160 (total number of coins) 5n + 10d = 1050 (total value). And I have thought through to the answer.