Since the smallest of these currency values (the nickel) is equal to 5 cents, the number of five cent coins that go into a dollar is equal to 20. It is impossible to have a combination of 35 nickels and dimes whose sum is exactly equal to a dollar.
dimes : all coins = 6 : 12+6+18 = 6 : 36 = 1×6 : 6×6 = 1 : 6 Dimes are ⅙ of all coins.
This is only possible if you allow adding coinsNumber of coins in row x Number of rows = total number of coins5 x 2 = 10 coins4 x 4 = 20 coinsYou would need 10 more coins
8 of them.
If all coins were dimes he would have $1.30. Every quarter that replaces a dime increases the total by 15c. The total has to be increased by $1.20 which is 15c x 8. He has 8 quarters and 5 dimes.
Since the smallest of these currency values (the nickel) is equal to 5 cents, the number of five cent coins that go into a dollar is equal to 20. It is impossible to have a combination of 35 nickels and dimes whose sum is exactly equal to a dollar.
It depends on the currency.Current US coins are limited to $1 so the number of coins to reach $19.95 will be 24. Nineteen $1 coins, three quarters and two dimes.In times gone by, US currency included $10 and $5 coins so the number was once lower than the current 24 coins.UK currency has a £2 coin so £19.95 will require 14 coins. Nine £2 coins, one £1 coin, one 50 pence, two 20 pence coins and a 5 pence coin.
A lot
A multiple of 11 can't be a prime number.
One
The smallest is 55.
20 - 10 of each
You have provided insufficient information to answer the question. You would need to tell either (i) the total number of coins or (ii) the exact total value.
If n is the number of nickels and d the number of dimes, then the equations are:n + d = 160 (total number of coins) 5n + 10d = 1050 (total value). And I have thought through to the answer.
One estimate places to total number of coins in circulation at about 30 billion.
The smallest number is LCM(2, 3, 4, 5, 6) + 1 = 61
The total number of outcomes is 2^5 = 32.