0
Add your answer:
Earn +20 pts
What is Y2 plus 8y plus 16 equals 0?
y2 +8y + 16 = 0 can factor to (y+4) (y+4) = 0 so y+4 = 0 so y = -4
What is 66-3y plus y2 from 88 plus 5y-y2?
88 + 5y - y2 66 - 3y + y2 Subtract: 22 + 8y -2y2
Find the center and radius of the circle given by the equation x2 plus y2-10x plus 8y plus 5 equals 0?
The standard equation of a circle with center C(h,k) and radius r is as follows:(x - h)2 + (y - k)2 = r2(x2 -2hx +h2) + (y2 - 2ky + k2)We have...x2 + y2 - 10x + 8y + 5 =0x2 - 10x + y2 + 8y + 5 =0add h2 and k2 to both sides(x2 - 10x + h2) + (y2 + 8y + k2) = -5 + h2 + k2Using the above framework we can see that 10 = 2h, h = 5Using the above framework we can see that 8 = 2k, k = 4So the formula is(x2 - 10x + 25) + (y2 + 8y + 16) = -5 + 25 + 16(x - 5)2 + (y - 4)2 = 36the center of the circle is C(5,4) and radius 6
Find the radius of a circle with the equation x2 plus y2 equals 16?
x2 +y2 = R2 =16 = radius 2 R = 4
The equation of a circle centered at the origin is x2 plus y2 16. What is the radius of the circle?
If that equals 16 then the radius is 4
What is Y2 plus 8y plus 16 equals 0?
y2 +8y + 16 = 0 can factor to (y+4) (y+4) = 0 so y+4 = 0 so y = -4
Factor y2-8y plus 15?
It goes to (x-5)(x-3)
What is the answer to y2 plus 8y plus 7?
If you mean y2+8y+7=0 then it is a quadratic. y2+8y+7+9-9=0 y2+8y+16-9=0 (y+4)2=9 y+4=3 , y+4=-3 y=-1 , y=-7 So y can equal -1 or -7.
What is 66-3y plus y2 from 88 plus 5y-y2?
88 + 5y - y2 66 - 3y + y2 Subtract: 22 + 8y -2y2
What is the perimeter of the curve x2 plus y2-12x-8y-43 equals 0?
Let's first reformat it: x2 + y2 - 12x - 8y - 43 = 0 x2 - 12x + 36 + y2 - 8y + 16 = 43 + 36 + 16 (x - 6)2 + (y - 4)2 = 95 So this equation defines a circle, with a center point at (6, 4) and a perimeter (i.e. circumference) of √95.
Factor y2-10y plus 16?
(y - 8)(y - 2)
Find the center and radius of the circle given by the equation x2 plus y2-10x plus 8y plus 5 equals 0?
The standard equation of a circle with center C(h,k) and radius r is as follows:(x - h)2 + (y - k)2 = r2(x2 -2hx +h2) + (y2 - 2ky + k2)We have...x2 + y2 - 10x + 8y + 5 =0x2 - 10x + y2 + 8y + 5 =0add h2 and k2 to both sides(x2 - 10x + h2) + (y2 + 8y + k2) = -5 + h2 + k2Using the above framework we can see that 10 = 2h, h = 5Using the above framework we can see that 8 = 2k, k = 4So the formula is(x2 - 10x + 25) + (y2 + 8y + 16) = -5 + 25 + 16(x - 5)2 + (y - 4)2 = 36the center of the circle is C(5,4) and radius 6
How do you factor the expression y2 plus 6y - 16?
(y + 8)(y - 2)
Which value of c makes y2 8y c a perfect square trinomial?
I'm going to go out on a limb and assume that y2 8y c actually means y^2 + 8y + c c = 16 makes a perfect square: (y + 4)^2 = (y+4)*(y+4) = y^2 + 8y + 16
Factor the expression y4-256?
y4 - 256 = (y2 - 16)(y2 + 16) = (y - 4)(y + 4)(y2 + 16)
What is the solution to x2 plus 2y-6x plus 8y-1 equals x2-y2 plus 4x-6y-1?
x2 + 2y - 6x + 8y - 1 = x2 - y2 + 4x + 6y - 1 y2 - 10x + 4y = 0 y(y+4) = 10x It cannot be solved completely because with two variables (x and y) you need two independent equations for a full solution.
What is the center and radius of the graph of the circle of x squared plus y squared plus 6x minus 8y minus 24 0?
x2 + y2 + 6x + 8y - 24 = 0 add 32, 42, and 24 to both sides to complete the squares (x2 + 6x + 32) + (y2 + 8y + 42) = 9 + 16 + 24 (x + 3)2 + (y + 4)2 = 49 [x - (-3)]2 + [y - (-4)]2 = 72 Center: (-3, -4) Radius: 7
