23 x 10 = 230
_//(2*2) - 4x - 7// * _//2// = 0 4* 12x - 7 * 122/100 = 0 28*12x * ((28*12)/122) = 0 (23/10 * x) * ((23/10 * x)/122) = 0 23/10 *x = 0 / ((23/10 *x)122) 23/10 *x = 0 23/x = 10 x = 2.3
23/10 x 100 = 230 percent.
two hundred and thirty23 x 10 = 230
10 over 6, which is the same as (10 x 9 x 8 x 7 x 6 x 5) / (1 x 2 x 3 x 4 x 5 x 6).
6022 = 6.022 x 103
To convert from moles to number of objects, the conversion factor is Avogadro's number (6.022 x 10^23 objects per mole). To convert from number of objects to moles, the conversion factor is the reciprocal of Avogadro's number (1 mole per 6.022 x 10^23 objects).
There are 2.49 moles in 1.50 x 10^23 entities. This is calculated by dividing the number of entities by Avogadro's number, which is 6.022 x 10^23 entities/mol.
23 x 10 = 230
_//(2*2) - 4x - 7// * _//2// = 0 4* 12x - 7 * 122/100 = 0 28*12x * ((28*12)/122) = 0 (23/10 * x) * ((23/10 * x)/122) = 0 23/10 *x = 0 / ((23/10 *x)122) 23/10 *x = 0 23/x = 10 x = 2.3
23 x 10 = 230
2.3 x 10 = 23
23 = (2 x 10) + (3 x 1)
8.45 x 10^23 = 845,000,000,000,000,000,000,000
23/10 x 100 = 230 percent.
23 kg in Scientific Notation = 2.3 x 10^1 kgThe kilo- prefix means ``x 10^3''→ 23 kg = 2.3 x 10^1 x 10^3 g = 2.3 x 10^4 g
1.00 mole is always 6.022*10+23 particles (of any kind)So divide 3.70*10+23 (electrons) by this number 6.022*10+23 (electrons/mole of electrons) and you'll get the number of moles of electrons.It is 3.70 / 6.022 = 0.614 mole of electrons