Well, honey, a division problem where the quotient is larger than the dividend is technically not possible in the realm of real numbers. You see, division is all about breaking things down into smaller parts, so it's like trying to fit a big ol' watermelon into a tiny little cup - just ain't gonna happen. Stick to addition if you want to see numbers grow, sweetie.
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A division problem where the quotient is larger than the dividend is not possible in traditional arithmetic. The quotient is the result of dividing the dividend by the divisor, and it represents how many times the divisor can be subtracted from the dividend. If the quotient is larger than the dividend, it would imply that the divisor is larger than the dividend, which is mathematically incorrect in a standard division operation.
The answer is 0 times with a remainder of 17. When dividing 17 by 19, the divisor is larger than the dividend, so the division cannot be completed evenly. The quotient would be 0, and the remainder would be the original dividend, which is 17 in this case.
Because you can take a piece of an apple out of a bag of apples more times than the number of whole apples in the bag.
It's easier to visualize with smaller numbers. 18 divided by 3 = 6 18 divided by 6 = 3 If the dividend is the same, the smaller the divisor, the larger the quotient.
There are two main methods:Euclid's methodChoose one of the numbers to be the dividend of a division and the other to be the divisor.Perform the divisionIgnore the quotient and keep the remainderIf the remainder is zero, the last divisor is the GCDReplace the dividend by the divisorReplace the divisor by the last remainderRepeat from step 2.It doesn't matter which number is the dividend and which is the divisor of the first division, but if the larger is chosen as the divisor, the first run through the steps above will swap the two over so that the larger becomes the dividend and the smaller the divisor - it is better to choose the larger as the dividend in the first place. Prime factorisationExpress the numbers in their prime factorisations in power format. Multiply the common primes to their lowest power together to get the GCD.The first is limited to two numbers, but the latter can be used to find the gcd of any number of numbers.Examples:GCD of 500 and 240:Euclid's method:500 ÷ 240 = 2 r 20 240 ÷ 20 = 6 r 0gcd = 20Prime factorisation:500 = 22 x 53 240 = 24 x 3 x 5gcd = 22 x 5 = 20
Rules for dividing by a fraction are multiply by the reciprocal. The reciprocal of a unit fraction is a whole number. Multiplying by a whole number will make the answer (quotient) larger. ex unit fraction 1/a 7 divided by 1/a = 7 x a/1 = 7a .... a times larger than 7.