There are 2 numbers that go into both 10 and 12. They are 1 and 2.
It is: 1
5 and 1 both go into 10 and 5.
12 and 5/6 - 8 and 1/4 To solve this problem, subtract the whole numbers first. 12 - 8 = 4. Now we can work on the nasty little fractions! 5/6 - 1/4. In order to add or subtract fractions, we need to have a common denominator, that is, the same number on the bottom of BOTH fractions. 6 and 4 aren't the same, so we'll need to multiply and find a number that is the same. Are there any numbers both 6 and 4 can go into evenly? Don't pick a large number, start small. Well, 6 can go into 12 evenly. and 4 can also go into 12 evenly! OK, how many times does 6 go into 12? 2 times. We need to multiply 5/6 * 2/2 to get a 12 on the bottom. 5/6 * 2/2 = 10/12 (try reducing this fraction, see if 10/12 = 5/6) How many times will 4 go into 12? 3 times, that's right. Now multiply 1/4 * 3/3 = 3/12 (reduce 3/12 to lowest terms to check) So, since 5/6 = 10/12 and 1/4 = 3/12 --> 10/12 - 3/12 When adding or subtraction fractions, the bottom has to be the same. (Check!) Add or subtract fraction top numbers ONLY! Keep the same bottom number. 10/12 - 3/12 = 7/12. Combine this with the whole number we calculated earlier and we get: 12 and 5/6 - 8 and 1/4 = 4 and 7/12
2 goes into 12 6 times and into 14 7 times Two go's into both numbers. As 2x6=12 and 2x7=14.
There are 2 numbers that go into both 10 and 12. They are 1 and 2.
The number that can go into 6 and 10 are 1 2 5 and 10. The following list can be used to clarify this further: 1 can go into both 6 and 10 2 can go into both 6 and 10 5 can go into both 6 and 10 10 can go into both 6 and 10This means that the number that can go into 6 and 10 is 1 2 5 and 10.
The first number that 12 and 16 go into is 48.
It is: 1
they all go into 120
The LCM of the numbers 6 and 12 is 12. This is lowest number that will go into both number evenly.
Any multiple of 60. There are an infinite number of them.
The LCM of 8 and 10 is 40
The LCM of 45 and 10 is 90
2, 3 and 12.
The LCM of both numbers is 924
Any multiple of 132.