The sum of two squares cannot be factored. It can be represented thus:
a^2 + b^2 = (a + bi)(a - bi)
In this expression, the i is the symbol for the imaginary number the square root of -1.
A squared + B squared = C squared.
Assuming A, B, and C are the three sides of a right triangle, also assuming C is the hypotenuse.
you use A squared plus B squared equals C squared
4
This expression can be factored. ab + 3a + b2 + 3b = a(b + 3) + b(b + 3) = (a + b)(b + 3)
The sum of two squares cannot be factored. If that's -a^2 + b^2, that's b^2 - a^2, which factors to (b - a)(b + a)
It's the square root of a2+b2. It cannot be simplified. It is NOT a+b. The answer is c square.
It is: 2b squared
(a + 2 - b) (a + 2 + b)
(a+b)2
No. If you expand (a + b)2 you get a2 + 2ab + b2. This is not equal to a2 + b2
b= 10
b = 14324.80366
(a+b)(a squared-ab+b squared)
The Pythagoream Thereom is a^2 + b^2 = c^2. Written out it is a squared plus b squared equals c squared.
a=b=3.60555
4
It simplifies to 5a+4 !
(2a + b)(a + 3b)