ab-2ac+b^2-2bc
(b-c)(a+b)-ac
ac + 2ad + 2bc + 4bd = a(c + 2d) + 2b(c + 2d) = (a + 2b)(c + 2d) Now expand to confirm your answer: c(a + 2b) + 2d(a + 2b) = ac + 2bc + 2ad + 4bd ≡ ac + 2ad + 2bc + 4bd
To factor the expression 3ab + 3ac + 2b^2 + 2bc, we first look for common factors among the terms. We can factor out a 3a from the first two terms, and a 2 from the last two terms. This gives us 3a(b + c) + 2(b^2 + bc). Next, we notice that we can factor out a b from the second term in the second parenthesis, giving us the final factored form: 3a(b + c) + 2b(b + c).
ac - 3ad - 2bc + 6bd = a(c - 3d) - 2b(c - 3d) = (a - 2b)(c - 3d)
ab-2ac+b^2-2bc
(b-c)(a+b)-ac
(a + b)(b - 2c)
(a + b)(b - 2c)
(a+b+c)²=a²+b²+c²+ 2ab+2bc+2ac
(a+b-c)2 = a2 + b2 +c2 +2ab - 2bc - 2ac
Surface area = 2ab + 2bc + 2ac
a2+2ab+b2+2ac+2bc+c2+2ad+2ae+2bd+2be+2cd+2ce+d2+2de+e2
(2a + b)(2c + d)
(a + 2b)(c + 2d)
(2a + b)(2c + d)
(2a + b)(2c + d).