Any three digit number which is in the four times table. E.g 100, 104, 108 ... 992, 996.
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∙ 2010-05-13 18:14:51120
The greatest 4 digit integer divisible by 3 (and therefore a multiple of 3) is 9999.
what is the largest three-digit number that is divisible by 4, 5, and 6
4- last two digits are a multiple of 4 7-take the last digit and subtract it from the rest of the number and if multiple of 7 (including 0) 8- last three digits are multiple of 8
To be divisible by both 4 and 9 a number must be a multiple of the Least Common Factor of 4 and 9. The LCM is 36. The first 3 digit number in each hundred that is a multiple of 36 are as follows :- 108, 216, 324, 432, 504, 612, 720, 828 and 900.
240
104
Anything three-digit would have to be a multiple, like 280.
9984 is the largest 4-digit multiple of 32
It is a 4 digit multiple of 6.
There are lots and lots of numbers three-digit numbers that are common multiples of 4 and 6. The first that comes to mind is 600. The lowest such number is 108. The highest is 996.
The greatest 4-digit number that is divisible by 16 is 9984
120
Add the last digit (units digit) to twice the previous digit (tens digit). If this sum is divisible by 4, so is the original number.
If last two digits of a number are divisible by 4 then number is a multiple of 4 for a number with more than 21 digit
The greatest 4 digit integer divisible by 3 (and therefore a multiple of 3) is 9999.
Any multiple of four must be even; any number ending in three is odd. Look at the multiples of four from 1 to 9. They are in the order : 4,8,12,16,20,24,28,32,36. Now, any number when multiplied by 4, will have the one's digit as the one's digit of the above multiples In the above multiples, no multiple has 3 as the one's digit, i.e., no multiple ends in three. Take an example. 15x4 will have 0 in the one's digit because 5x4 = 20 and has 0 in the one's place.