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Think of the 20 identical triangles that are formed inside the polygon when you draw line segments from the centre of the polygon to each of the polygons corners.
The angles of those triangles at the centre of the polygon add to 360 degrees, and there are 20 of them. Therefore, each of the angles of the triangles at the centre is 360 / 20 = 18 degrees.
The angles within each triangle add to 180 degrees. Therefore the other two angles within each triangle, away from the centre of the polygon, add to 180 - 18 = 162 degrees. The two angles are equal. Therefore each angle is 162 / 2 = 81 degrees.
Each interior angle of the 20-sided polygon consists of two of these angles. Therefore, the interior angle is 2 x 81 or 162 degrees.
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What is the size of an interior angle of a 20 sided regular polygon?
exterior angle = 360° ÷ 20 sides = 18° interior angle = 180° - exterior angle = 180° - 18° = 162°
What is the sum of the interior angles of a twenty sided polygon?
Use the formula below to calculate the sum of the interior angles of any polygon with n-number of sides: n * (180o) - 360o or (n-2) * 180o And to find the measurement of each interior angle divide this number by the number of sides of the polygon. So for a 20-sided polygon, the sum of the interior angles would be: 20*180o - 3600 = 3240o or (20-2) * 180o = 3240o And each interior angle would measure 3240o/20 or 162o == ==
Find the number of sides a regular polygon must have to meet each condition each exterior angle measure is one eigth the measure of each interior angle?
An exterior angle of a regular polygon and its corresponding interior angle = 180° If an exterior angle is 1/8 of the interior angle (A) then A + A/8 = 180 : 9A = 1440 : A = 160 Each exterior angle is thus 180 -160 = 20° The number of sides = 360 ÷ exterior angle = 360 ÷ 20 = 18
How many side has a polygon got if the interior angle is 162 degrees?
Assuming every interior angle is the same, and they're all 162 degrees, the shape would have 20 sides.
What is the exterior angle of an 18 sided shape?
The exterior angle of a 18 sided shape is 360/18 =20 degrees The exterior angle is always 360 divided by the numbe of sides of that polygon. =) what the hell im i doing answering this?
What is the sum of the interior angle measures of a 20-sided polygon?
3240
What is sum of the interior angle measures of a 20 sided polygon?
3240
What is the interior angle of a regular 23 sided polygon?
164o 20' 52.17''
What are the interior angles of a 20 sided polygon?
If the 20-sided polygon is a regular polygon, then:The sum of all 20 angles = (20 - 2)180⁰ = 18(180⁰) = 3240⁰Each angle measure = 3240⁰/20 = 162⁰
What is the size of an interior angle of a 20 sided regular polygon?
exterior angle = 360° ÷ 20 sides = 18° interior angle = 180° - exterior angle = 180° - 18° = 162°
What is the total interior angle of a regular polygon if 20 triangles can be drawn inside the polygon?
20 triangles will fit into a 22 sided polygon whose interior angles add up to 3600 degrees
What is the sum of the interior angle measured by a 20-sided polygon?
162o. Method 1: Sum of interior angles of n-sided polygon = (2n - 4) right angles. In this case n = 20 so total of interior angles is 36 x 90o. Assuming polygon is regular then each interior angle is (36 x 90) divided by 20 = 3240/20 = 162. Method 2: Exterior angles of regular n-sided polygon = 360/n which in this case = 360/20 =18. Straight line is 180o so interior angle = (180 - exterior angle) = 180 - 18 = 162.
What is the sum of the interior angles of a twenty sided polygon?
Use the formula below to calculate the sum of the interior angles of any polygon with n-number of sides: n * (180o) - 360o or (n-2) * 180o And to find the measurement of each interior angle divide this number by the number of sides of the polygon. So for a 20-sided polygon, the sum of the interior angles would be: 20*180o - 3600 = 3240o or (20-2) * 180o = 3240o And each interior angle would measure 3240o/20 or 162o == ==
What is the measure of each interior angle of a twenty side polygon?
Interior angle of any n-sided polygon = (2n - 4) x 90/n degrees in this case n = 20 so you have 36 x 90/20 = 162o
What is the measure of an angle of a regular 20-sided polygon?
The interior angles of an n-sided polygon add to (n-2)*180 degrees. So the interior angles of a 20-gon add to 18*180 = 3240 degrees. The 20-gon is regular so each angle is a 20th of this ie 3240/20 = 162 deg.
If the exterior angle of a regular polygon is 20 what is the interior angle of this polygon?
160
What Is the sum of the angles of an 20 sided polygon?
The interior angles of a 20 sided polygon add up to 3240 degrees
