Best Answer

If the 20-sided polygon is a regular polygon, then:

The sum of all 20 angles = (20 - 2)180⁰ = 18(180⁰) = 3240⁰

Each angle measure = 3240⁰/20 = 162⁰

Q: What are the interior angles of a 20 sided polygon?

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The interior angles of a 20 sided polygon add up to 3240 degrees

The interior angles of an x-sided polygon would be: (x - 2) * 180. (20 - 2) * 180 = 3,240

It is a regular 20 sided polygon

The sum of the interior angles in a n-sided polygon is (n-2) x 180o. For a 20 sided polygon: sum_interior_angles = (20 - 2) x 180o = 18 x 180o = 3240o.

3240o. The sum of the interior angles of a n sided polygon is sum = (n - 2) x 180o An icosagon has 20 sides, thus the sum of its interior angles is: sum = (20 - 2) x 180o = 3240o

Related questions

The interior angles of a 20 sided polygon add up to 3240 degrees

The interior angles of an x-sided polygon would be: (x - 2) * 180. (20 - 2) * 180 = 3,240

The interior angles add up to 3240 degrees

The interior angles of a 20 sided polygon add up to 3240 degrees

Sum of interior angles of n-sided polygon = 180n - 360 degrees. When n = 20 this gives 3240o

There are 20 interior angles and they add up to 3240 degrees

The interior angles add up to 3240 degrees

It is a regular 20 sided polygon

3240o

The sum of the interior angles in a n-sided polygon is (n-2) x 180o. For a 20 sided polygon: sum_interior_angles = (20 - 2) x 180o = 18 x 180o = 3240o.

3600 Degrees

3240o. The sum of the interior angles of a n sided polygon is sum = (n - 2) x 180o An icosagon has 20 sides, thus the sum of its interior angles is: sum = (20 - 2) x 180o = 3240o