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What is the value of the function f(x)3(4-x) when x7?
When x = 7, f(x) = 3*(4-x) = 3*(-3) = -9
What polynomial function below find F(-4) f(x)2x2-x plus 9?
f(x) = 2 * 2 - x + 9 f(-4) = 2 * 2 -(-4) + 9 f(-4) = 4 + 4 + 9 = 17
How can you write 1.76 repeating as a fraction?
Let F = 1.7666.... then 10*F = 17.6666.... So 10*F - F = 17.6666.... - 1.7666... 9*F = 15.9 F = 15.9/9 = 159/90 = 53/30
How do you solve the limits of a definite integral?
By using the fundamental theorem of Calculus. i.e. The integral of f(x) = F(x), your limits are [a,b]. Solve: F(b) - F(a). The FTC, second part, says that if f is a continuous real valued function of [a,b] then the integral from a to b of f(x)= F(b) - F(a) where F is any antiderivative of f, that is, a function such that F'(x) = f(x). Example: Evaluate the integral form -2 to 3 of x^2. The integral form -2 to 3 of x^2 = F(-2) - F(3) = -2^3/3 - 3^3/3 = -8/3 - 27/3 = -35/3
If the line tangent to the graph of the function f at the point 1 7 passes through the point -2 -2 then f prime of 1 is?
3 f'(1) is the slope of the tangent line of the curve at x=1. Because the tangent line at x=1 goes through (1,7) and (-2,-2), its slope is (7-(-2))/(1-(-2))=9/3=3. So f'(1)=3.
