FeCl3
n3 + 1 = n3 + 13 = (n + 1)(n2 - n + 12) = (n + 1)(n2 - n + 1)
Zn(s) → Zn2+(aq) + 2e- and Fe3+(aq) + e- → Fe2+(aq)
Let any number be n:- n3/n3 = n*n*n/n*n*n = 1 And in index form: n3/n3 = n3-3 = n0 = 1
n2+n3=n5 it's simple 8th grade pre-algebra
FeCl3
n3 + 3n2 + 4n + 12 = (n3 + 3n2) + (4n + 12) = n2(n + 3) + 4(n + 3) = (n2 + 4)(n + 3).
n3 + 1 = n3 + 13 = (n + 1)(n2 - n + 12) = (n + 1)(n2 - n + 1)
b. Fe3 plus ions
6+N3 is the sum of N*3 then you add six. 6*N3 is you multiply 6 times three times N times three.
To separate Fe3+ ions, one can use a reagent like ammonia (NH3) which forms a complex with Fe3+ ions called iron(III) hydroxide. This complex precipitates out of the solution, allowing for the separation of Fe3+ ions from other components in the mixture.
A. Fe^2+ ==> Fe^3+ + e- is an oxidation reactionB. Fe^3+ +e- ==> Fe^2+ is a reduction reactionC. Fe(s) ==> Fe(l) is neither an oxidation nor a reduction reaction. It is a phase change.D. Fe + 2e- ==> Fe^2+ is not a possible reaction.
K3n
Zn(s) → Zn2+(aq) + 2e- and Fe3+(aq) + e- → Fe2+(aq)
The correct chemical formula for a molecule of N3 and H+ would be NH4+, forming the ammonium ion.
Potassium thiocyanate can be used to confirm the oxidation of Fe2+ ions to Fe3+ ions by forming a blood-red complex with Fe3+, known as iron(III) thiocyanate. Upon the addition of potassium thiocyanate, if a blood-red color formation is observed, it indicates the presence of Fe3+ ions, confirming the oxidation of Fe2+ ions.
The ionic formula for Al3+ and N3- is AlN. Aluminum (Al) has a 3+ charge and nitrogen (N) has a 3- charge, so they combine in a 1:1 ratio to form a neutral compound.