n squared x n n x n x n = n cubed n x n = n squared n squared x n = n cubed
9y cubed plus 2y squared
sin cubed + cos cubed (sin + cos)( sin squared - sin.cos + cos squared) (sin + cos)(1 + sin.cos)
Helen is an ashole
Oh, dude, adding n squared plus n squared is like adding apples to apples, you know? It's just like, you take two n squared terms and you add them together to get 2n squared. It's not rocket science, man. Just double up those n squares and you're good to go.
n squared x n n x n x n = n cubed n x n = n squared n squared x n = n cubed
n3 + 8n2 + 12n = n(n+2)(n+6)
9y cubed plus 2y squared
105 squared plus 8 cubed is equal to 11,537.
The expression a^3 + b^3 can be factored using the sum of cubes formula, which states that a^3 + b^3 = (a + b)(a^2 - ab + b^2). Therefore, a^3 + b^3 can be factored as (a + b)(a^2 - ab + b^2). This formula helps us break down the sum of two cubes into a product of binomials, simplifying the expression.
n(2n - 1)(2n + 7)
The answer is 537
17.
200x
sin cubed + cos cubed (sin + cos)( sin squared - sin.cos + cos squared) (sin + cos)(1 + sin.cos)
if its x(squared) its 7x(cubed) if its 2xX its 14x(squared)
Helen is an ashole