It is 256.
3^(-2x + 2) = 81? log(3^(-2x + 2)) = log(81) (-2x+2)log(3) = log(81) -2x = log(81)/log(3) - 2 x = (-1/2)(log(81)/log(3)) + 1
9
9 x 9 = 81 because if you count 9 times it would make up or be 81
-9 squared = 81(-9)^2 = (-9) * (-9) = 81
It is 256.
Log base 3 of 81 is equal to 4, because 3 ^ 4 = 81. Therefore, two times log base 3 of 81 is equal to 2 x 4 = 8.
Check
3^(-2x + 2) = 81? log(3^(-2x + 2)) = log(81) (-2x+2)log(3) = log(81) -2x = log(81)/log(3) - 2 x = (-1/2)(log(81)/log(3)) + 1
The above question rewritten as an equation:81/100=0.95d or to put all the numbers in similar terms:.81=.95dIn order to solve for d, remember the logarithm definition: logax=N means that aN=xTherefore,log.9(.81)=5dSince logs are base 10, you need to change to base .9, to solve the left side of the equation:log10(.81)/log10(.9)=2Therefore: 2=5d or d=2/5 or 0.4
No it is not. The log of any number, with the same number as the base, is always 1.
log37 - log3x = 4 log3(7/x) = 4 7/x = 34 = 81 x = 7/81
If a right triangle has an area of 81 meters an a base of 9 meters its height is: 18 meters.
log9(x)=2 x=9^2 x=81
Area = (1/2) x base x height , so solve this for height; height = 2 x Area / base height = (2)(81)/(9) = 18
9(9) = 81 base 10. In base 4 it is 1101 (64 + 16 + 1), etc.
81 9*9=8181