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What is log base 4 of 16?
The logarithm base 4 of 16 is asking the question "4 raised to what power equals 16?" In this case, 4 squared is equal to 16, so the answer is 2. Therefore, log base 4 of 16 is equal to 2.
How do you solve the equation 5.2 log4 2x16?
Due to limitations with browsers mathematical operators (especially + =) get stripped from questions (leaving questions with not enough information to answer them) and it is not entirely clear what the log4 bit means. I guess that the log4 bit is logarithms to base 4 of 2x^16 (which I'll write as log_4(2x^16) for brevity). If this is so, use normal algebraic operations to make log_4(2x^16) the subject of the equation. With logs there are useful rules; given 2 numbers 'a' and 'b': log(ab) = log(a) + log(b) log(a^b) = b × log(a) Which means: log_4(2x^16) = log_4(2) + log_4(x^16) = log_4(2) + 16 × log(x) and the equation can be further rearranged: log_4(2x^16) = <whatever> → log_4(2) + 16 × log(x) = <whatever> → log(x) = (<whatever> - log_4(2)) / 16 Logarithms tell you the power to which the base of the logarithm must be raised to get its argument, for example when using common logs: lg 100 = 2 since 10 must be raised to the power 2 to get 100, ie 10² = 100. (lg is the abbreviation for logs to base 10; ln, or natural logs, is the abbreviation for logs to the base e.) With logs to base 4, it is 4 that is raised to the power of the log to get the original value. eg log_4(16) = 2 since 4^2 = 16. log_4(2) can be worked out: The log to any base of the base is 1 (since any number to the power 1 is itself). Now 2 × 2 = 2² = 4. → log_4(4) = 1 → log_4(2²) = 1 → 2 × log_4(2) = 1 → log_4(2) = ½ → log(x) = (<whatever> - ½) / 16 Back to the rearranged equation; with logs to base 4, if you make both sides the power of 4 you'll get: 4^(log_4(x)) = 4^(<whatever>) → x = 4^(<whatever>) which now solves for x.
Evaluate 2 to the power of 4?
What is 1+2 with sum
How do you evaluate 4 to the third power?
4^3 = 4*4*4 = 16*4 = 64
Evaluate 4 to the power of minus 2?
To evaluate 4 to the power of minus 2, you can rewrite it as 1 divided by 4 squared. This simplifies to 1 divided by 16, which equals 0.0625. The negative exponent indicates that the base should be taken as the reciprocal of the positive exponent value.
What is log base 4 of 16?
The logarithm base 4 of 16 is asking the question "4 raised to what power equals 16?" In this case, 4 squared is equal to 16, so the answer is 2. Therefore, log base 4 of 16 is equal to 2.
Which logarithm is equivalent to log base 3 16 - log base 3 2?
log316 - log32 = log38
How do you solve log base16 8?
You divide log 8 / log 16. Calculate the logarithm in any base, but use the same base for both - for example, ln 8 / ln 16.
How do you solve the equation 5.2 log4 2x16?
Due to limitations with browsers mathematical operators (especially + =) get stripped from questions (leaving questions with not enough information to answer them) and it is not entirely clear what the log4 bit means. I guess that the log4 bit is logarithms to base 4 of 2x^16 (which I'll write as log_4(2x^16) for brevity). If this is so, use normal algebraic operations to make log_4(2x^16) the subject of the equation. With logs there are useful rules; given 2 numbers 'a' and 'b': log(ab) = log(a) + log(b) log(a^b) = b × log(a) Which means: log_4(2x^16) = log_4(2) + log_4(x^16) = log_4(2) + 16 × log(x) and the equation can be further rearranged: log_4(2x^16) = <whatever> → log_4(2) + 16 × log(x) = <whatever> → log(x) = (<whatever> - log_4(2)) / 16 Logarithms tell you the power to which the base of the logarithm must be raised to get its argument, for example when using common logs: lg 100 = 2 since 10 must be raised to the power 2 to get 100, ie 10² = 100. (lg is the abbreviation for logs to base 10; ln, or natural logs, is the abbreviation for logs to the base e.) With logs to base 4, it is 4 that is raised to the power of the log to get the original value. eg log_4(16) = 2 since 4^2 = 16. log_4(2) can be worked out: The log to any base of the base is 1 (since any number to the power 1 is itself). Now 2 × 2 = 2² = 4. → log_4(4) = 1 → log_4(2²) = 1 → 2 × log_4(2) = 1 → log_4(2) = ½ → log(x) = (<whatever> - ½) / 16 Back to the rearranged equation; with logs to base 4, if you make both sides the power of 4 you'll get: 4^(log_4(x)) = 4^(<whatever>) → x = 4^(<whatever>) which now solves for x.
Evaluate 2 to the power of 4?
What is 1+2 with sum
How do you evaluate 4 to the 2nd power?
42 = 4*4 = 16
How do you solve 16 as a power of 2?
In this case, trial and error is probably the easiest: 22 = 4, 23 = 8, 24 = 16 yes! A more genral answer is: the power that you want is log(16)/log(2) where the logarithm is calculated to any base (10 or e , or indeed any other).
What is logarithm in simple terms?
A logarithm is the inverse operation of exponentiation. It is used to find the power to which a fixed number (called the base) must be raised to produce a given number. Logarithms help simplify calculations involving very large or very small numbers.
How do you evaluate 4 to the third power?
4^3 = 4*4*4 = 16*4 = 64
How do you write a number as a power of 2?
For an exact power of 2 (1, 2, 4, 8, 16, 32, etc., but also 1/2, 1/4, etc.), you can try out different exponents until you get it right. To write any number (greater than 0) as a power of 2 is equivalent to taking the logarithm of that number in base 2, which is the same (if you call your number "n") as calculating log n / log 2 (using the same base for both logarithms - for example, both in base 10, or both in base e).
Evaluate 4 to the power of minus 2?
To evaluate 4 to the power of minus 2, you can rewrite it as 1 divided by 4 squared. This simplifies to 1 divided by 16, which equals 0.0625. The negative exponent indicates that the base should be taken as the reciprocal of the positive exponent value.
Can you give an example of an evaluation question in math?
Evaluate: 4x + 16 = 32 4x + 16 -16 = 32 - 16 4x = 16 x = 4 evaluate basically means manipulate and find the answer
