Perimeter: just add the sides. 13+13+7+7= 40
Area: multiply the length by the width. 13x7= 91
Make sure to put the unit of measurement too! :) (oh, by the way, I'm guessing this is a rectangle)
Yes.
Area = 49 cm2 => length of side = 7 cmThen perimeter = 4*7 = 28 cm.Area = 49 cm2 => length of side = 7 cmThen perimeter = 4*7 = 28 cm.Area = 49 cm2 => length of side = 7 cmThen perimeter = 4*7 = 28 cm.Area = 49 cm2 => length of side = 7 cmThen perimeter = 4*7 = 28 cm.
The perimeter is 18 feet.
To calculate the area of a triangle with side lengths of 11cm, 8cm, and 7cm, we first need to determine the semi-perimeter of the triangle. The semi-perimeter (s) is calculated by adding all three sides together and dividing by 2, so s = (11 + 8 + 7) / 2 = 13 cm. Next, we can use Heron's formula to find the area of the triangle, which is given by the formula: Area = √[s(s-a)(s-b)(s-c)], where a, b, and c are the side lengths. Plugging in the values, we get Area = √[13(13-11)(13-8)(13-7)] = √[1325*6] = √780 ≈ 27.93 cm².
The area of square is the square of one of its sides, which are all equal. To find the value of a side, take the square root of the area. In this case the square root of 49cm2 is 7cm. The perimeter is the sum of all four sides of the square, so the perimeter of a square with an area of 49cm2 is 7+7+7+7 = 28, or 4x7 = 28.
The area of a square is the (perimeter/4)^2. The perimeter is 52, so 52/4=13. 13^2 is 169. The area of the square is 169 cm.^2.
It is an isosceles triangle with a perimeter of 26+(4 times square root of 13) linear units and an area of 78 square units
The sides of square are equal,and when they have given you the area and asked for perimeter,it means that you have to look for the square root of the area which will be one side and that is 13.perimeter=side ×4 which is 13×4=52.
You can't tell. The perimeter doesn't tell you the area. There are an infinite number of rectangles that all have the same perimeter but different areas. Here are a few that all have perimeters of 28 cm: 1 x 13 . . . . . Area = 13 2 x 12 . . . . . Area = 24 3 x 11 . . . . . Area = 33 4 x 10 . . . . . Area = 40 5 x 9 . . . . . Area = 45 6 x 8 . . . . . Area = 48 7 x 7 . . . . . Area = 49
For a square, the area is the length of a side squared and the perimeter is 4 times the length. If the area is 49, then the length of a side is 7. The perimeter is then 4 times 7, or 28.
Yes.
56
7mm x 4mm = 28mm squared = Area // (7+7)+(4+4) = 22mm = Perimeter
Perimeter = 24 inches Area = 35 square inches
Perimeter:20 inches Area:35
Area = 49 cm2 => length of side = 7 cmThen perimeter = 4*7 = 28 cm.Area = 49 cm2 => length of side = 7 cmThen perimeter = 4*7 = 28 cm.Area = 49 cm2 => length of side = 7 cmThen perimeter = 4*7 = 28 cm.Area = 49 cm2 => length of side = 7 cmThen perimeter = 4*7 = 28 cm.
The shape which minimises the perimeter for a fixed area is a circle. A circle of radius 7.334 ft (approx) will have the required area and a perimeter (circumference) of just 46.084 ft. The quadrilateral with the smallest perimeter will be a square with sides of 13 feet: a perimeter of 4*13 = 52 feet. Any regular polygon with more than 4 sides will have a smaller perimeter, for the same area, than a square.