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How many possible combinations is there with 1379?
To calculate the number of possible combinations of the digits 1, 3, 7, and 9, we can use the formula for permutations of a set of objects, which is n! / (n-r)!. In this case, there are 4 digits and we want to find all possible 4-digit combinations, so n=4 and r=4. Therefore, the number of possible combinations is 4! / (4-4)! = 4! / 0! = 4 x 3 x 2 x 1 = 24. So, there are 24 possible combinations using the digits 1, 3, 7, and 9.
Is a set of consonants an infinite or finite?
It is finite, but there would be many possible combinations.
I have a Lock with 3 wheels and the digits 0 to 9 on it. what is the most combinations possible?
10 possible numbers on each wheel equals 10x10x10 or 1000 combinations possible.
How many possible combinations are there of 9 numbers from 20 drawn numbers?
There are 167960 combinations.
How many 3 letter combinations can be made from this set ABCDEFG if no letter can be repeated?
You did not give us the set to work with...
How can you Find the number of combinations of objects in a set?
The number of R-combinations in a set of N objects is C= N!/R!(N-R)! or the factorial of N divided by the factorial of R and the Factorial of N minus R. For example, the number of 3 combinations from a set of 4 objects is 4!/3!(4-3)! = 24/6x1= 4.
How many possible combinations is there with 1379?
To calculate the number of possible combinations of the digits 1, 3, 7, and 9, we can use the formula for permutations of a set of objects, which is n! / (n-r)!. In this case, there are 4 digits and we want to find all possible 4-digit combinations, so n=4 and r=4. Therefore, the number of possible combinations is 4! / (4-4)! = 4! / 0! = 4 x 3 x 2 x 1 = 24. So, there are 24 possible combinations using the digits 1, 3, 7, and 9.
How many combinations of 4 numbers can be made from the set of numbers 246789?
If the numbers are allowed to repeat, then there are six to the fourth power possible combinations, or 1296. If they are not allowed to repeat then there are only 360 combinations.
You are designing a new game in which you will choose a set of 3 numbers from 15 and a set of 2 from 20 How many possible combinations are there?
86,450
Is the number of permutations of two items from a data set is always two times the number of combinations when taking two objects at a time from the same data set?
Yes
Is a set of consonants an infinite or finite?
It is finite, but there would be many possible combinations.
What possible combinations using 4 character A-Z?
140 possible combinations
What are the combinations of 5 objects to get 120?
you can have 5 24 objects to 120
What is the selection of objects from a collection called?
Combinations.
If you have a set of 40 numbers how do you calculate the number of all the possible combinations of 5 numbers from the set?
By making a number tree that could have as many as 1,000,000 combos.
How do you find all the combinations of a list?
To find the number of combinations possible for a set of objects, we need to use factorials (a shorthand way of writing n x n-1 x n-2 x ... x 1 e.g. 4! = 4 x 3 x 2 x 1). If you have a set of objects and you want to know how many different ways they can be lined up, simply find n!, the factorial of n where n is the number of objects. If there is a limit to the number of objects used, then find n!/(n-a)!, where n is the number of objects and n-a is n minus the number of objects you can use. For example, we have 10 objects but can only use 4 of them; in formula this looks like 10!/(10-4)! = 10!/6!. 10! is 10 x 9 x 8 x ... x 1 and 6! is 6 x 5 x ... x 1. This means that if we were to write out the factorials in full we would see that the 6! is cancelled out by part of the 10!, leaving just 10 x 9 x 8 x 7, which equals 5040 i.e. the number of combinations possible using only 4 objects from a set of 10.
Four different sets of objects contain 2 4 6 and 7 objects respectively. How many unique combinations can be formed by picking one object from each set?
336 2 possibilities for the first for each of these two you have 4 possibilities for the second - making it 8 for each of these 8 you have 6 possibilities for the third - making it 48 possibilities for each of those 48 you have 7 possibilities for the fourth - making it 336 possible combinations 2x4x6x7 = 336
