To calculate the number of possible combinations of the digits 1, 3, 7, and 9, we can use the formula for permutations of a set of objects, which is n! / (n-r)!. In this case, there are 4 digits and we want to find all possible 4-digit combinations, so n=4 and r=4. Therefore, the number of possible combinations is 4! / (4-4)! = 4! / 0! = 4 x 3 x 2 x 1 = 24. So, there are 24 possible combinations using the digits 1, 3, 7, and 9.
There are 167960 combinations.
If repeats are allowed than an infinite number of combinations is possible.
3,124,550 possible combinations
56 combinations. :)
105 = 100000
There are millions of possible combinations.
If order doesn't matter, 15 combinations and if order does matter, 360 combinations are possible.
2^n possible combinations
There are 2^5 = 32 different combinations of the five traits possible.
There are 167960 combinations.
Since a number can have infinitely many digits, there are infinitely many possible combinations.
Four outcomes, three combinations.
1379
If repeats are allowed than an infinite number of combinations is possible.
There are 5,040 combinations.
3,124,550 possible combinations
35