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Does the number of permutations always exceed the number of combinations?

No. The number of permutations or combinations of 0 objects out of n is always 1. The number of permutations or combinations of 1 object out of n is always n. Otherwise, yes.


How do you find permutation?

If there are n objects and you have to choose r objects then the number of permutations is (n!)/((n-r)!). For circular permutations if you have n objects then the number of circular permutations is (n-1)!


The number of permutations of n objects taken all together is?

The number of permutations of n objects taken all together is n!.


How many 4 number combinations are there using 1 2 3 4 5?

There are 120 permutations and 5 combinations.


How many5 number combinations are there in the numbers1to43?

On a calculator: 43C5 = 962598 This is for combinations and not permutations, so in essence, the order of the 5 number combinations does not matter. Yours Truly, Mr Greatness


How many different combinations are possible is a coin is tossed once and a number cube is tossed twice?

The number of combinations - not to be confused with the number of permutations - is 2*21 = 42.


Is the number of permutations of 2 items from the same data set always 2 times the number of combiations when taking 2 objects from a data set?

Yes


The number of permutations of 5 things taken 2 at a time is 20?

Not quite. Number of combinations is 20, number of permutations is 10. Any 2 from 5 is 10 but in any order doubles this.


How many 3 number combinations are possible with 1234?

Just 4: 123, 124, 134 and 234. The order of the numbers does not matter with combinations. If it does, then they are permutations, not combinations.


How can you find the number of permutations of a set of objects?

If there are n different objects, the number of permutations is factorial n which is also written as n! and is equal to 1*2*3*...*(n-1)*n.


How many different permutations are there of 4 objects taken 4 at a time?

The number of different permutations of 4 objects taken 4 at a time is calculated using the formula ( n! ), where ( n ) is the number of objects. For 4 objects, this is ( 4! = 4 \times 3 \times 2 \times 1 = 24 ). Therefore, there are 24 different permutations.


What is the number of distinguishable permutations?

The formula for finding the number of distinguishable permutations is: N! -------------------- (n1!)(n2!)...(nk!) where N is the amount of objects, k of which are unique.