Yes
No. The number of permutations or combinations of 0 objects out of n is always 1. The number of permutations or combinations of 1 object out of n is always n. Otherwise, yes.
There are 120 permutations and 5 combinations.
On a calculator: 43C5 = 962598 This is for combinations and not permutations, so in essence, the order of the 5 number combinations does not matter. Yours Truly, Mr Greatness
The number of combinations - not to be confused with the number of permutations - is 2*21 = 42.
If there are n different objects, the number of permutations is factorial n which is also written as n! and is equal to 1*2*3*...*(n-1)*n.
No. The number of permutations or combinations of 0 objects out of n is always 1. The number of permutations or combinations of 1 object out of n is always n. Otherwise, yes.
If there are n objects and you have to choose r objects then the number of permutations is (n!)/((n-r)!). For circular permutations if you have n objects then the number of circular permutations is (n-1)!
The number of permutations of n objects taken all together is n!.
There are 120 permutations and 5 combinations.
On a calculator: 43C5 = 962598 This is for combinations and not permutations, so in essence, the order of the 5 number combinations does not matter. Yours Truly, Mr Greatness
The number of combinations - not to be confused with the number of permutations - is 2*21 = 42.
Yes
Not quite. Number of combinations is 20, number of permutations is 10. Any 2 from 5 is 10 but in any order doubles this.
Just 4: 123, 124, 134 and 234. The order of the numbers does not matter with combinations. If it does, then they are permutations, not combinations.
If there are n different objects, the number of permutations is factorial n which is also written as n! and is equal to 1*2*3*...*(n-1)*n.
The number of different permutations of 4 objects taken 4 at a time is calculated using the formula ( n! ), where ( n ) is the number of objects. For 4 objects, this is ( 4! = 4 \times 3 \times 2 \times 1 = 24 ). Therefore, there are 24 different permutations.
The formula for finding the number of distinguishable permutations is: N! -------------------- (n1!)(n2!)...(nk!) where N is the amount of objects, k of which are unique.