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How do you calculate delta e if q equals 1.78 kJ and w equals -862 J?
863.78
Q plus r equals s so t plus u equals?
v
P-q and q-p are logically equivalent prove?
p --> q and q --> p are not equivalent p --> q and q --> (not)p are equivalent The truth table shows this. pq p --> q q -->(not)p f f t t f t t t t f f f t t t t
Q-2.4 equals 1.8 q equals?
1.8q = q - 2.4 1.8q - q = -2.4 0.8q = -2.4 q = -2.4/0.8 q = -2.9999
What is the truth table for negation p or negation q?
P Q (/P or /Q) T T F T F T F T T F F T
What percent of copper in ore is cost efficient to mine?
Q=MC(DELTA)t
What is the Relationship between mass and temperature?
if q= mc delta T then we know that as the mass increases the heat transferred increases
What is the equation for specific equations?
Q = mc(delta)T Q = quantity of heat energy m = mass c = specific heat capacity different constant for each different substance (delta)T = difference in temperature (subtract high temp - low temp)
If 705g of water is heated 889J how much will its temperature increase?
To find the temperature increase, you can use the formula: ( Q = mc\Delta T ), where ( Q ) is the heat energy transferred, ( m ) is the mass of the substance, ( c ) is the specific heat capacity of the substance, and ( \Delta T ) is the change in temperature. Rearrange the formula to solve for ( \Delta T ) by dividing both sides by ( mc ): ( \Delta T = \frac{Q}{mc} ). Substitute ( Q = 889J ), ( m = 705g = 0.705kg ), ( c = 4.18 J/g°C ), and calculate to find the change in temperature.
Why is the triangle symbol in front of the T but not the Q in the equation Q equals m x T x C?
That equation is, q(Joules) = mass * specific heat ( symbol is C ) * (delta, a triangle) change in temperature That is to say delta means, Temperature Final - Temperature Initial q is a constant and not subject to change as temperature is
What is the formula to find specific heat of water Q?
The formula to find the specific heat of water ( Q ) is: ( Q = mc\Delta T ), where (m) is the mass of the water, (c) is the specific heat capacity of water, and ( \Delta T ) is the change in temperature of the water.
How many degrees will 340 J raise the temperature of 6.8g of water?
To find the temperature change, we need to use the formula: ( Q = mc\Delta T ), where ( Q ) is the heat, ( m ) is the mass, ( c ) is the specific heat capacity of water (4.18 J/g°C), and ( \Delta T ) is the temperature change. Substituting the values, we get: ( 340 = 6.8 \times 4.18 \times \Delta T ). Solving for ( \Delta T ), we find that the temperature will rise by approximately 12.75 degrees Celsius.
Q equals m plus x t plus c In this equation what does Q t and c represent?
In the equation Q equals m plus x t plus c, Q represents the total quantity or value being measured or calculated. t represents the variable or time period being observed or measured. c represents the constant term or the y-intercept, which is the value of Q when t equals zero.
Suppose you want to heat 40g of water by 20 degrees Celsius how many joules of heat are required?
Use the equation q=mc(delta t) (that is, heat equals mass times specific heat times the change in temperature) to answer the question. The specific heat of water is 4.186 Joules per gram-Celsius. Therefore, q=(40)(4.186)(20), which equals 3348.8 Joules of heat (or approximately 3.35 kiloJoules of heat).
How do you calculate delta e if q equals 1.78 kJ and w equals -862 J?
863.78
How do you calculate Delta E if q equals 1.40 kJ and w equals -657 J?
658.4
What is the calculation for specific heat?
Q=cm(delta)T "Q" is the heat "C" is the specific heat "m" is the mass "(delta)T" is the change in temperature * just plug in what you have and then solve for what you don't have...and thats how you find the specific heat of a substance.
