How heat is calculated in thermodynamics.
Heat = mass x specific heat capacity x change in temperature.
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p --> q and q --> p are not equivalent p --> q and q --> (not)p are equivalent The truth table shows this. pq p --> q q -->(not)p f f t t f t t t t f f f t t t t
1.8q = q - 2.4 1.8q - q = -2.4 0.8q = -2.4 q = -2.4/0.8 q = -2.9999
P Q (/P or /Q) T T F T F T F T T F F T
Q=MC(DELTA)t
if q= mc delta T then we know that as the mass increases the heat transferred increases
Q = mc(delta)T Q = quantity of heat energy m = mass c = specific heat capacity different constant for each different substance (delta)T = difference in temperature (subtract high temp - low temp)
That equation is, q(Joules) = mass * specific heat ( symbol is C ) * (delta, a triangle) change in temperature That is to say delta means, Temperature Final - Temperature Initial q is a constant and not subject to change as temperature is
== Q== mc(delta)T == Q=thermal energy m= mass c=specific heat (ex. water is 4.184 J/goc) deltaT= change in temperature
In the equation Q equals m plus x t plus c, Q represents the total quantity or value being measured or calculated. t represents the variable or time period being observed or measured. c represents the constant term or the y-intercept, which is the value of Q when t equals zero.
Q=mc∆T
Use the equation q=mc(delta t) (that is, heat equals mass times specific heat times the change in temperature) to answer the question. The specific heat of water is 4.186 Joules per gram-Celsius. Therefore, q=(40)(4.186)(20), which equals 3348.8 Joules of heat (or approximately 3.35 kiloJoules of heat).
To calculate the enthalpy change or heat energy of a phase change, use the formula q=m(heat of (fusion, vaporization, etc...)). Make sure to use the formula q=mc(delta T) to calculate the heat energy for the temperature changes in between phase changes. Add up all of the q values and you have your enthalpy change.
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Q=cm(delta)T "Q" is the heat "C" is the specific heat "m" is the mass "(delta)T" is the change in temperature * just plug in what you have and then solve for what you don't have...and thats how you find the specific heat of a substance.