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What else can I help you with?
How do you calculate delta e if q equals 1.78 kJ and w equals -862 J?
863.78
How much heat is required to raise the temperature of 10 pounds of water from 50F to?
To calculate the heat required to raise the temperature of 10 pounds of water from 50°F to a specific temperature, you can use the formula: [ Q = mc\Delta T ] where ( Q ) is the heat energy (in BTUs), ( m ) is the mass (in pounds), ( c ) is the specific heat capacity of water (approximately 1 BTU/lb°F), and ( \Delta T ) is the change in temperature (in °F). For example, if you want to raise it to 150°F, the temperature change (( \Delta T )) would be 100°F, so the heat required would be: [ Q = 10 , \text{lb} \times 1 , \text{BTU/lb°F} \times 100°F = 1000 , \text{BTUs} ] Adjust ( \Delta T ) based on your target temperature.
Q plus r equals s so t plus u equals?
v
P-q and q-p are logically equivalent prove?
p --> q and q --> p are not equivalent p --> q and q --> (not)p are equivalent The truth table shows this. pq p --> q q -->(not)p f f t t f t t t t f f f t t t t
Q-2.4 equals 1.8 q equals?
1.8q = q - 2.4 1.8q - q = -2.4 0.8q = -2.4 q = -2.4/0.8 q = -2.9999
What variable represents thermal energy in the equation q equals MC delta t?
In the equation ( q = mc\Delta T ), the variable ( q ) represents thermal energy. It quantifies the amount of heat energy absorbed or released by a substance, where ( m ) is the mass, ( c ) is the specific heat capacity, and ( \Delta T ) is the change in temperature.
What percent of copper in ore is cost efficient to mine?
Q=MC(DELTA)t
What variable represents thermal energy in the equation Q equals mcT?
In the equation ( Q = mc\Delta T ), the variable ( Q ) represents thermal energy. Here, ( m ) is the mass of the substance, ( c ) is the specific heat capacity, and ( \Delta T ) is the change in temperature. The equation calculates the amount of thermal energy absorbed or released by a substance when its temperature changes.
What is the Relationship between mass and temperature?
if q= mc delta T then we know that as the mass increases the heat transferred increases
What is the equation for specific equations?
Q = mc(delta)T Q = quantity of heat energy m = mass c = specific heat capacity different constant for each different substance (delta)T = difference in temperature (subtract high temp - low temp)
If 705g of water is heated 889J how much will its temperature increase?
To find the temperature increase, you can use the formula: ( Q = mc\Delta T ), where ( Q ) is the heat energy transferred, ( m ) is the mass of the substance, ( c ) is the specific heat capacity of the substance, and ( \Delta T ) is the change in temperature. Rearrange the formula to solve for ( \Delta T ) by dividing both sides by ( mc ): ( \Delta T = \frac{Q}{mc} ). Substitute ( Q = 889J ), ( m = 705g = 0.705kg ), ( c = 4.18 J/g°C ), and calculate to find the change in temperature.
How do you calculate specific heat for anfo?
To calculate the specific heat of ANFO (Ammonium Nitrate Fuel Oil), you can use the formula: ( Q = mc\Delta T ), where ( Q ) is the heat added, ( m ) is the mass of the ANFO, ( c ) is the specific heat, and ( \Delta T ) is the change in temperature. By rearranging the formula to solve for ( c ) gives ( c = \frac{Q}{m\Delta T} ). You would need to experimentally determine ( Q ) by measuring the heat energy supplied, ( m ) as the mass of ANFO, and ( \Delta T ) as the temperature change during the process.
If 60 J of heat is added to an aluminum can with a mass of 24.7 g what is its temperature change Specific heat capacity of aluminum is 0.903 J g and 8728 C .?
To calculate the temperature change (( \Delta T )) of the aluminum can, we can use the formula ( Q = mc\Delta T ), where ( Q ) is the heat added, ( m ) is the mass, and ( c ) is the specific heat capacity. Rearranging to find ( \Delta T ), we have ( \Delta T = \frac{Q}{mc} ). Substituting the values: [ \Delta T = \frac{60 , \text{J}}{24.7 , \text{g} \times 0.903 , \text{J/g°C}} \approx 2.68 , \text{°C}. ] Thus, the temperature change of the aluminum can is approximately 2.68 °C.
How many degrees will J raise the temperature of g of water?
To determine how many degrees J will raise the temperature of g of water, we need to use the specific heat capacity formula: ( Q = mc\Delta T ), where ( Q ) is the heat added (in joules), ( m ) is the mass of the water (in grams), ( c ) is the specific heat capacity of water (approximately 4.18 J/g°C), and ( \Delta T ) is the change in temperature (in °C). Rearranging the formula gives ( \Delta T = \frac{Q}{mc} ). Without specific values for Q and g, we cannot calculate the exact change in temperature.
What variable represents specific heat in the equation Qmc delta t?
In the equation ( Q = mc\Delta T ), the variable that represents specific heat is ( c ). It denotes the amount of heat required to raise the temperature of one unit mass of a substance by one degree Celsius (or one Kelvin). The other variables in the equation are ( Q ) for heat energy, ( m ) for mass, and ( \Delta T ) for the change in temperature.
What is the formula to find specific heat of water Q?
The formula to find the specific heat of water ( Q ) is: ( Q = mc\Delta T ), where (m) is the mass of the water, (c) is the specific heat capacity of water, and ( \Delta T ) is the change in temperature of the water.
How many degrees will 340 J raise the temperature of 6.8g of water?
To find the temperature change, we need to use the formula: ( Q = mc\Delta T ), where ( Q ) is the heat, ( m ) is the mass, ( c ) is the specific heat capacity of water (4.18 J/g°C), and ( \Delta T ) is the temperature change. Substituting the values, we get: ( 340 = 6.8 \times 4.18 \times \Delta T ). Solving for ( \Delta T ), we find that the temperature will rise by approximately 12.75 degrees Celsius.
