There are 6 sides to a rectangular prism. Two are 5x3, two are 3x2 and two are 2x5 - that means two are 15mm squared, two are 6mm squared, and two are 10mm squared. Add those up, and you get 62mm squared.
The surface area of a prism is twice the area of the end plus the area of all the sides. For a prism with a polygon cross-section the area of all the sides if given by the perimeter of the cross-section polygon multiplied by the length of the prism. Assuming you have a prism of cross-section that is a rectangle with sides 4 mm and 3 mm, and is 15 mm long (ie it is an oblong), its surface area is: → surface_area = 2 × (4 mm × 3 mm) + 2 × (4 mm + 3 mm) × 15 mm → surface area = 2 × 12 mm² + 14 mm × 15 mm = 234 mm²
find the surface area of each solid to the nearest tenth.(use n=3.14). a=10 mm b=14 mm c=14 mm
2700
6*12*12 = 864 square mm
Standard CDs have a diameter of 120 mm; that would be a radius of 60 mm. Since area is calculated as the value of pi (3.1416) times the square of the radius, we calculate as follows: Area A = pi X r2 = 3.1416 X 60 mm X 60 mm = 3.1416 X 3600 mm2 = 11,309.76 mm2. That value translates to 113.0976 square centimeters or 17.5301631 square inches. The area just calculated includes the hole. If you wish the hole excluded, so you have just the surface area of the disk, subtract the area of the hole, which has a diameter of 15 mm. The hole, with a radius of 7.5 mm, has an area of 176.715 mm2. Subtracting that from the area of a circle with a 120 mm diameter (11,309.76 mm2), we get a true surface area of 11,133.045 mm2 or 17.2562543 in2.
76 square mm
2x(3x5+3x4+4x5) = 94 sq mm
It is: 2(3*5)+2(5*8)+2(3*8) = 104 square mm
The surface area of a prism is twice the area of the end plus the area of all the sides. For a prism with a polygon cross-section the area of all the sides if given by the perimeter of the cross-section polygon multiplied by the length of the prism. Assuming you have a prism of cross-section that is a rectangle with sides 4 mm and 3 mm, and is 15 mm long (ie it is an oblong), its surface area is: → surface_area = 2 × (4 mm × 3 mm) + 2 × (4 mm + 3 mm) × 15 mm → surface area = 2 × 12 mm² + 14 mm × 15 mm = 234 mm²
Surface area = 2*(2*6 + 6*2 + 2*2) = 2*(12 + 12 + 4) = 2*28 = 56 square mm.
9005493
A cylinder if the diameter is 124 mm and the length is 170 mm has a surface area of 90,377.34mm2
There is no such thing as a rectangular container since a rectangle is a 2-dimensional concept whereas a container is 3-dimensional. It could be 12 cm x 12 cm x 13.1250 cm which has a surface area of 918 sq cm. or 1 cm x 1 cm x 1890 cm with a surface area of 7562 sq cm or 1 mm x 1 mm x 189 metres with a surface area of 75600.02 sq cm.
To calculate the surface area of an ISMB 200, you need to know its dimensions. The ISMB 200 is an Indian Standard Medium Weight Beam, and its dimensions are: Height: 200 mm Width: 100 mm Flange thickness: 10.2 mm Web thickness: 5.7 mm Length: Typically supplied in standard lengths of 6, 9, 12, or 15 meters To calculate the surface area of an ISMB 200, you need to find the surface area of each of its parts separately and then add them up. The surface area of the flanges and the web can be calculated as follows: Surface area of each flange = Width × Flange thickness × 2 = 100 mm × 10.2 mm × 2 = 2040 mm² Surface area of the web = Height × Web thickness = 200 mm × 5.7 mm = 1140 mm² Total surface area of an ISMB 200 = Surface area of both flanges + Surface area of the web = (2040 mm² + 2040 mm²) + 1140 mm² = 5220 mm² Therefore, the surface area of an ISMB 200 is 5220 square millimeters.
Total surface area = 2*(LW + WH + HL) = 538.76 sq mm.
Assuming that the jewel case is in the shape of a cuboid, the total surface area is 38280 sq mm.
Surface area of the ball = 4*pi*342 = 4624*pi square mm