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Q: What is the 10th term of 5n plus 1?

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(3n+2)(n+1)

249

t(n) = 5n - 3

1st term= 3 2nd term = 5 Nth term = 2n+1 10th term= 21 = 2(10)+1

That factors to (2n + 1)(n + 2)

Related questions

4 over 5n

(2n+3)(n+1)=2n2+5n+3.

9 - 5n + 1 = 15 -5n = 15 - 10 n = -5/5 n = -1

(3n+2)(n+1)

5n + 1 = 10 + 2n5n - 2n + 1 - 1 = 10 - 1 + 2n - 2n3n = 93n/3 = 9/3n = 3

It is 1 + 5N.

249

t(n) = 5n - 3

1st term= 3 2nd term = 5 Nth term = 2n+1 10th term= 21 = 2(10)+1

(5n + 1)(n + 7)

9-5n+1 = 15 -5n = 15-9-1 -5n = 5 Divide both sides of the equation by -5 to find the value of n: n = -5

That factors to (2n + 1)(n + 2)

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