Each term seems to be double of the previous number starting with 3.
Hence 4th term = 24 and 5th is 48
3n
The nth term is 18 -3n and so the next term will be 3
t(n) = 3*n
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
3n
The nth term is 18 -3n and so the next term will be 3
It is 60.
12/20 = 6/10 = 3/5
12÷36=6÷18=3÷9=1÷3 ie. 12÷36=1÷3
t(n) = 3*n
It is: -3072
It is: -3072
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
The sequence 0, 3, 6, 9, 12 is an arithmetic sequence where the first term is 0 and the common difference is 3. The formula for the nth term can be expressed as ( a_n = 3(n - 1) ) or simply ( a_n = 3n - 3 ). This formula generates the nth term by multiplying the term's position (n) by 3 and adjusting for the starting point of the sequence.
12 is the LCM of any of the following 44 sets:{12},{1, 12}, {2, 12}, {3, 4}, {3, 12}, {4, 6} , {4, 12}, {6, 12},{1, 2, 12}, {1, 3, 4}, {1, 3, 12}, {1, 4, 6}, {1, 4, 12},{1, 6, 12}, {2, 3, 4}, {2, 3, 12}, {2, 4, 6}, {2, 4, 12},{2, 6, 12}, {3, 4, 6}, {3, 4, 12}, {3, 6, 12}, {4, 6, 12},{1, 2, 3, 12}, {1, 2, 4, 12}, {1, 2, 6, 12}, {1, 3, 4, 12},{1, 3, 6, 12}, {1, 4, 6, 12}, {1, 2, 4, 6}, {1, 3, 4, 6},{1, 2, 3, 4}, {2, 3, 4, 6}, {2, 3, 4, 12}, {2, 3, 6, 12},{2, 4, 6, 12}, {3, 4, 6, 12},{1, 2, 3, 4, 6}, {1, 2, 3, 4, 12}, {1, 2, 3, 6, 12},{1, 2, 4, 6, 12}, {1, 3, 4, 6, 12}, {2, 3, 4, 6, 12},{1, 2, 3, 4, 6, 12}.