t(n) = 3*n
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12 - 5(n-1)
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
The nth term in this sequence is 4n + 3.
The nth term of the sequence is 2n + 1.