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10650056950806. It is calculated by adding one to the last number and multiplying it by itself.
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The sixth number of the Fibonacci sequence?
The 6th number of the Fibonacci sequence is 8.0 + 0 = 00 + 1 = 11 + 1 = 21 + 2 = 32 + 3 = 53 + 5 = 8Notice how it is the 6th equation meaning its the 6th Fibonacci number.Note that some people like to use 1 twice instead of 0.http://en.wikipedia.org/wiki/Fibonacci_number
What is the 6th term of the Fibonacci Sequence?
the answer is 8
Which rule will find the nth term of the arithmetic sequence -58 -65 -72 -86?
It appears that a number of -79 is missing in the sequence and so if you meant -58 -65 -72 -79 -86 then the nth term is -7n-51 which makes 6th term in the sequence -93
What number comes next in the sequence 1 2 6 42 1806?
Option 1The sequence is found by multiplying each term by the number one greater than itself. First, 1 * 2 = 2. Then, 2 * 3 = 6. Then, 6 * 7 = 42, and so on.n*(n+1) = x (where n equals the previous x)1*(1+1) = 22*(2+1) = 66*(6+1) = 4242*(42+1) = 18061806*(1806 +1) = 3,263,442.Another way to consider it is that each term is being squared then added plus the original amount, so the second term will be equal to the first term squared, then add the first term.We find the equation (n^2) + n , where n is the previous term.So the next term is again 3,263,442.Option 2 For this option, we take each number and multiply it by the subsequent prime number, beginning in the same values and then diverging from the first choice.First we take 1 and multiply it by the smallest prime greater than itself - 2, and get 2.The next prime after 2 is 3 which gives us 2 * 3 = 6.Six times the next prime, 7, gives us 42.The number 42 times its nearest greater prime of 43 gives us 1806.Finally, 1806 times the next prime number (which is 1811) gives us 3,270,666.Option 3 The third approach to this series is a long process but seems logical too.Lets start. The original series is:1, 2, 6, 42, 1806, ?The second digit can be derived by multiplying the first digit by 2. Then the third digit can be derived by multiplying the second digit by 3. Then the fourth digit is third digit times 7. The fifth is fourth digit multiplied by 43.So we had a second string of series of multipliers which consists: 2,3,7,43,?To get the fifth multiplier, a pattern can be seen from this series. The second digit is first digit is multiplied by 1 plus 1. The third digit is second digit multiplied by 2 plus 1. The fourth digit is third digit multiplied by 6 plus 1.This in turn has created the sequence 1, 2, 6 which in the sequential nature of these sequences seems to be created by multiplying by subsequent integers. So the next term would be 6 * 4 = 24.Going back to the multipliers we find that the fifth digit is 1033 (24 * 43).2, 3, 7, 43, 1033Again, the second digit is the first digit multiplied by 1 plus 1. The third digit is the second digit multiplied by 2 plus 1. The fourth digit is the third digit multiplied by 6 plus 1. The fifth digit is now the fourth digit multiplied by 24 plus 1.Now lets go back to the original series:1, 2, 6, 42, 1806, ?Now we see the sixth digit is the fifth digit multiplied by 1033 which gives us 1,865,598.* * * * *Yet another possibility is to fit a polynomial to the given sequence. There are infinitely many polynomials of order 5 or above but considerT(n) = (1667n^4 - 16554n^3 + 57685n^2 - 82158n + 39384)/24.For n = 1, 2, 3, 4 and 5 it gives the required 5 numbers and T(6) = 8661.In reality, short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.3,263,44210,650,056,950,806 etcThe formula is X2 + XSimplest way is:n=n*(n+1).=== === === === === === other way: 1 2 12*1/2=6 .... 1 2 6 126*2/6=42 ..... 1 2 6 42 12642*6/42=1806 .... 1 2 6 42 1806 12642186*42/1806=2940042 .... 1 2 6 42 1806 2940042There are at least two possible answers:1. You could fit the polynomial function:tn = (1667n4 - 16554n3 + 57685n2 - 82158n + 39384)/24 for n = 1, 2, 3, ...Following the logic, the 6th term is 8661.2. One alternative ist1 = 1 and tn+1 = tn*(tn + 1) for n = 1, 2, 3, ...That definition gives the next term as 3,263,442.There are many other solutions.1806*1807=32634423,263,442 comes after 1806. The series is formed by a number multiplying itself increased by 1. Here is the equation: X(X+1) Y1(1+1) 22(2+1) 66(6+1) 4242(42+1) 18061806(1806+1) 3,263,442In simpler numbers,1 X 2 22 X 3 66 X 7 4242 X 43 18061806 X 1807 3,263,4423263442. The progression is n(n+1).1 2 6 42 1'806 3'263'442 10'650'056'960'806 1st is 12nd is 1st*(1st+1) -> 1*23rd is 2nd*(2nd+1) -> 2*34th is 3rd*(3rd+1) -> 6*75th is 4th*(4th+1) -> 42*43...and so on32634423263442
What is the product of the 6th squared number and the 5th squared number?
jhuhuhu
It is said that engineers take 3 minutes to resolve this architects 3 hours and doctors 6 hours If you guess which the 6th number is you'll be able to open the excel file Once you discover it pu?
It is said that engineers take 3 minutes to resolve this, architects>3 hours and doctors 6 hours. If you guess the 6th number, you can>open the excel file by using the number as the password. Once you>discover it, put your name in, save it and send it on. What is the>6th number?>1, 2, 6, 42, 1806, ______?3263442
The sixth number of the Fibonacci sequence?
The 6th number of the Fibonacci sequence is 8.0 + 0 = 00 + 1 = 11 + 1 = 21 + 2 = 32 + 3 = 53 + 5 = 8Notice how it is the 6th equation meaning its the 6th Fibonacci number.Note that some people like to use 1 twice instead of 0.http://en.wikipedia.org/wiki/Fibonacci_number
Where was Elizabeth Barrett born?
Born in Kelloe. County Durham, England. 6th March 1806
What is the 6th term of the Fibonacci Sequence?
the answer is 8
What are the first four terms of a sequence when the nth term equals 3 to the power of n and what term number is 729 in the sequence?
The first four terms are 3 9 27 81 and 729 is the 6th term.
Which rule will find the nth term of the arithmetic sequence -58 -65 -72 -86?
It appears that a number of -79 is missing in the sequence and so if you meant -58 -65 -72 -79 -86 then the nth term is -7n-51 which makes 6th term in the sequence -93
What is the 6th number in this pattern 4 9 16 25?
Those are square numbers. Just continue getting more square numbers to continue the sequence.
What number comes next in the sequence 1 2 6 42 1806?
Option 1The sequence is found by multiplying each term by the number one greater than itself. First, 1 * 2 = 2. Then, 2 * 3 = 6. Then, 6 * 7 = 42, and so on.n*(n+1) = x (where n equals the previous x)1*(1+1) = 22*(2+1) = 66*(6+1) = 4242*(42+1) = 18061806*(1806 +1) = 3,263,442.Another way to consider it is that each term is being squared then added plus the original amount, so the second term will be equal to the first term squared, then add the first term.We find the equation (n^2) + n , where n is the previous term.So the next term is again 3,263,442.Option 2 For this option, we take each number and multiply it by the subsequent prime number, beginning in the same values and then diverging from the first choice.First we take 1 and multiply it by the smallest prime greater than itself - 2, and get 2.The next prime after 2 is 3 which gives us 2 * 3 = 6.Six times the next prime, 7, gives us 42.The number 42 times its nearest greater prime of 43 gives us 1806.Finally, 1806 times the next prime number (which is 1811) gives us 3,270,666.Option 3 The third approach to this series is a long process but seems logical too.Lets start. The original series is:1, 2, 6, 42, 1806, ?The second digit can be derived by multiplying the first digit by 2. Then the third digit can be derived by multiplying the second digit by 3. Then the fourth digit is third digit times 7. The fifth is fourth digit multiplied by 43.So we had a second string of series of multipliers which consists: 2,3,7,43,?To get the fifth multiplier, a pattern can be seen from this series. The second digit is first digit is multiplied by 1 plus 1. The third digit is second digit multiplied by 2 plus 1. The fourth digit is third digit multiplied by 6 plus 1.This in turn has created the sequence 1, 2, 6 which in the sequential nature of these sequences seems to be created by multiplying by subsequent integers. So the next term would be 6 * 4 = 24.Going back to the multipliers we find that the fifth digit is 1033 (24 * 43).2, 3, 7, 43, 1033Again, the second digit is the first digit multiplied by 1 plus 1. The third digit is the second digit multiplied by 2 plus 1. The fourth digit is the third digit multiplied by 6 plus 1. The fifth digit is now the fourth digit multiplied by 24 plus 1.Now lets go back to the original series:1, 2, 6, 42, 1806, ?Now we see the sixth digit is the fifth digit multiplied by 1033 which gives us 1,865,598.* * * * *Yet another possibility is to fit a polynomial to the given sequence. There are infinitely many polynomials of order 5 or above but considerT(n) = (1667n^4 - 16554n^3 + 57685n^2 - 82158n + 39384)/24.For n = 1, 2, 3, 4 and 5 it gives the required 5 numbers and T(6) = 8661.In reality, short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.3,263,44210,650,056,950,806 etcThe formula is X2 + XSimplest way is:n=n*(n+1).=== === === === === === other way: 1 2 12*1/2=6 .... 1 2 6 126*2/6=42 ..... 1 2 6 42 12642*6/42=1806 .... 1 2 6 42 1806 12642186*42/1806=2940042 .... 1 2 6 42 1806 2940042There are at least two possible answers:1. You could fit the polynomial function:tn = (1667n4 - 16554n3 + 57685n2 - 82158n + 39384)/24 for n = 1, 2, 3, ...Following the logic, the 6th term is 8661.2. One alternative ist1 = 1 and tn+1 = tn*(tn + 1) for n = 1, 2, 3, ...That definition gives the next term as 3,263,442.There are many other solutions.1806*1807=32634423,263,442 comes after 1806. The series is formed by a number multiplying itself increased by 1. Here is the equation: X(X+1) Y1(1+1) 22(2+1) 66(6+1) 4242(42+1) 18061806(1806+1) 3,263,442In simpler numbers,1 X 2 22 X 3 66 X 7 4242 X 43 18061806 X 1807 3,263,4423263442. The progression is n(n+1).1 2 6 42 1'806 3'263'442 10'650'056'960'806 1st is 12nd is 1st*(1st+1) -> 1*23rd is 2nd*(2nd+1) -> 2*34th is 3rd*(3rd+1) -> 6*75th is 4th*(4th+1) -> 42*43...and so on32634423263442
When was David dale born?
If this David Dale was a Scottish merchant and businessman then he was born 6th January 1739 and died March 17th 1806.
Which is the 6th composite number?
12 is the 6th composite number.
What is the next number in the sequence 7 6 4 6 2 6 1 6?
1 is a possibility because: I believe that this sequence has two parts. It is an alternating sequence. It has a repeated pattern of 6s as the second number and 4th and 6th and 8th etc. The first number and third and fith, etc. goes down by a number which goes down each time. So it is: 7-3 6+/- 0 4-2 6+/- 0 2-1 6+/- 0 1-0 6+/- 0 1-1 6+/- 0 0 (etc.) But simply the answer could be many things but 1 is the answer I found first.
What is the sixth term in the following arithmetic sequence 13 2 -9 -20?
Any number you like.If you fit a linear equation, Un = 24 - 11n then the 6th term is 42.However,Vn = (-29x4 + 290x3 - 1015x2 + 790x + 744)/60 gives the sequence 13, 2, -9, -20, -42.6, and -100Wn = (7x4 - 70x3 + 245x2 - 570x + 648)/20 gives the sequence 13, 2, -9, -20, -22.6, and 0whileXn = (71x4 - 710x3 + 2485x2 - 4210x + 3144)/60 gives the sequence 13, 2, -9, -20, -2.6, and 100By suitable choice of polynomial, any number at all can be in sixth place.
