It is possible to find a polynomial of degree 5 such that it can be made to fit the pattern of the above five numbers and any number at all that is chosen to be the eighth.
However, the simplest polynomial of degree 4 is
Un = 36n4 - 336n3 + 1128n2 - 1568n + 741 for n = 1, 2, 3, ...
and accordingly, the 8th term is 35,813.
It is 917969.
To find the 8th term of the pattern, we first need to identify the pattern itself. Looking at the numbers given, we can see that each subsequent number is obtained by multiplying the previous number by 5 and then subtracting 1. So, the pattern is: 3, 35-1=14, 145-1=69, 695-1=344, 3445-1=1719. Continuing this pattern, the 8th term would be 6249.
90
The given sequence is the sequence of perfect squares starting from 1. The nth term of this sequence can be represented as n^2. Therefore, the 8th term would be 8^2, which equals 64. So, the 8th term of the sequence 1, 4, 9, 16, 25 is 64.
It is: 1 1 2 3 5 8 13 and 21 which is the 8th term
It is 917969.
77
654
To find the 8th term of the pattern, we first need to identify the pattern itself. Looking at the numbers given, we can see that each subsequent number is obtained by multiplying the previous number by 5 and then subtracting 1. So, the pattern is: 3, 35-1=14, 145-1=69, 695-1=344, 3445-1=1719. Continuing this pattern, the 8th term would be 6249.
The formula is 6n + 7 where n is the nth term So 8th term would be (6 x 8) + 7 = 48 + 7 = 55
If you have this series: 1,2,3,4,5,6,7,8The 8th term is 8 and the n-th term is n.But if you have this series: 2,4,6,8,10,12,14,16The 8th term is 16 and the n-th term is 2n
90
The given sequence is the sequence of perfect squares starting from 1. The nth term of this sequence can be represented as n^2. Therefore, the 8th term would be 8^2, which equals 64. So, the 8th term of the sequence 1, 4, 9, 16, 25 is 64.
It is: 1 1 2 3 5 8 13 and 21 which is the 8th term
90
1/8th
48