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LCM[(13b3)3, 7b2] = LCM[2197b9, 7b2] = 2197*7*b9 = 15379*b9
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The question is somewhat ambiguous: the answers are LCM[3T2, 5T] =15T2 or LCM[(3T)2, 5T] =45T2
LCM is 20, which is the multiple of the highest power of prime factors in the given numbers (22 x 5).The LCM is 20.
LCM is 27, which is the multiple of the highest power of prime factors in the given numbers (33).