Oh, what a happy little question! To find the Least Common Multiple (LCM) of 2b^2 and 6c^3, first, we break down the numbers into their prime factors. The LCM is the product of all the highest powers of all prime factors in both numbers, so the LCM of 2b^2 and 6c^3 is 6b^2c^3. Just like painting a beautiful landscape, simplifying math problems can be quite calming and enjoyable.
To find the least common multiple (LCM) of 2b^2 and 6c^3, we first need to factorize both terms. The prime factorization of 2b^2 is 2 * b * b, and the prime factorization of 6c^3 is 2 * 3 * c * c * c. To find the LCM, we take the highest power of each prime factor that appears in either term, which gives us 2 * 3 * b^2 * c^3 = 6b^2c^3. Therefore, the LCM of 2b^2 and 6c^3 is 6b^2c^3.
-2b + 7 -3b = 2 -2b +7 -3b +2b = 2 + 2b 7 -3b + 3b = 2 + 2b +3b 7-2 = 2-2 + 2b + 3b 5 = 5b 1 = b
If you mean: 2c+2+6c-4 then it is 8c-2 when simplified.
-2
The question is somewhat ambiguous: the answers are LCM[3T2, 5T] =15T2 or LCM[(3T)2, 5T] =45T2
To find the least common multiple (LCM) of 2b^2 and 6c^3, we first need to factorize both terms. The prime factorization of 2b^2 is 2 * b * b, and the prime factorization of 6c^3 is 2 * 3 * c * c * c. To find the LCM, we take the highest power of each prime factor that appears in either term, which gives us 2 * 3 * b^2 * c^3 = 6b^2c^3. Therefore, the LCM of 2b^2 and 6c^3 is 6b^2c^3.
12b2c3
The Least Common Multiple (LCM) for 2 6 7 is 42.
Assuming you mean 2b^-6, with the 2b not in parenthesis, it simplifies to 2/b6, or 2 over b to the sixth.
-2b + 7 -3b = 2 -2b +7 -3b +2b = 2 + 2b 7 -3b + 3b = 2 + 2b +3b 7-2 = 2-2 + 2b + 3b 5 = 5b 1 = b
If you mean: 2c+2+6c-4 then it is 8c-2 when simplified.
-2
b3c2
The question is somewhat ambiguous: the answers are LCM[3T2, 5T] =15T2 or LCM[(3T)2, 5T] =45T2
To find the least common multiple (LCM) of two terms, we need to identify the highest power of each unique factor present in both terms. In this case, the LCM of a³b² and a²b⁵ would be a³b⁵, as it includes the highest power of both 'a' and 'b' present in either term. Therefore, the LCM of a³b² and a²b⁵ is a³b⁵.
8b + 11 - 3b = 2b + 2 5b + 11 = 2b + 2 5b - 2b = 2 - 11 3b = -9 b = -3
a = 2b - c a + c = 2b (a+c)/2 = b b = (a+c)/2