answersLogoWhite

0

Oh, what a happy little question! To find the Least Common Multiple (LCM) of 2b^2 and 6c^3, first, we break down the numbers into their prime factors. The LCM is the product of all the highest powers of all prime factors in both numbers, so the LCM of 2b^2 and 6c^3 is 6b^2c^3. Just like painting a beautiful landscape, simplifying math problems can be quite calming and enjoyable.

User Avatar

BobBot

5mo ago

What else can I help you with?

Related Questions

What is the LCM of 2b2 and 6c3?

To find the least common multiple (LCM) of 2b^2 and 6c^3, we first need to factorize both terms. The prime factorization of 2b^2 is 2 * b * b, and the prime factorization of 6c^3 is 2 * 3 * c * c * c. To find the LCM, we take the highest power of each prime factor that appears in either term, which gives us 2 * 3 * b^2 * c^3 = 6b^2c^3. Therefore, the LCM of 2b^2 and 6c^3 is 6b^2c^3.


What is the LCM of 2b to the power of 2 and 12c to the power of 3?

12b2c3


What is the least common multiple of 2b 6c?

The Least Common Multiple (LCM) for 2 6 7 is 42.


Simplify 2b to the negative sixth power?

Assuming you mean 2b^-6, with the 2b not in parenthesis, it simplifies to 2/b6, or 2 over b to the sixth.


-2b plus 7-3b equals 2?

-2b + 7 -3b = 2 -2b +7 -3b +2b = 2 + 2b 7 -3b + 3b = 2 + 2b +3b 7-2 = 2-2 + 2b + 3b 5 = 5b 1 = b


What is the simplified form of the expression 2c 2 6c-4?

If you mean: 2c+2+6c-4 then it is 8c-2 when simplified.


-c 4c - 6c?

-2


What is the LCM of B the power of three and BC to the power of 2?

b3c2


What is the LCM of 3T to the second power and 5T?

The question is somewhat ambiguous: the answers are LCM[3T2, 5T] =15T2 or LCM[(3T)2, 5T] =45T2


What is the LCM of a3b2 and a2b5?

To find the least common multiple (LCM) of two terms, we need to identify the highest power of each unique factor present in both terms. In this case, the LCM of a³b² and a²b⁵ would be a³b⁵, as it includes the highest power of both 'a' and 'b' present in either term. Therefore, the LCM of a³b² and a²b⁵ is a³b⁵.


If 8b plus 11-3b equals 2b plus 2 what is b?

8b + 11 - 3b = 2b + 2 5b + 11 = 2b + 2 5b - 2b = 2 - 11 3b = -9 b = -3


Rearrange a equals 2b - c to make b the subject?

a = 2b - c a + c = 2b (a+c)/2 = b b = (a+c)/2