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This is an example of an INDEPENDENT event:

The probability of throwing a double six with two dice is the result of throwing six with the first die and six with the second die. The total possibilities are, one from six outcomes for the first event and one from six outcomes for the second, Therefore (1/6) * (1/6) = 1/36th or 2.77%.

The two events are independent, since whatever happens to the first die cannot affect the throw of the second, the probabilities are therefore multiplied, and remain 1/36th.

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15y ago

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Anonymous

4y ago
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Q: What is the PROBABILITY of throwing 2 sixes with two dice?
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