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How do you do interquartile range step by step?
Step 1: Find the upper quartile, Q3.Step 2: Find the lower quartile: Q1.Step 3: Calculate IQR = Q3 - Q1.Step 1: Find the upper quartile, Q3.Step 2: Find the lower quartile: Q1.Step 3: Calculate IQR = Q3 - Q1.Step 1: Find the upper quartile, Q3.Step 2: Find the lower quartile: Q1.Step 3: Calculate IQR = Q3 - Q1.Step 1: Find the upper quartile, Q3.Step 2: Find the lower quartile: Q1.Step 3: Calculate IQR = Q3 - Q1.
Formula of quartile deviation?
Q3-q1
How many 10s in 850?
8500
How do you figure out which number is the outlier?
Find the inter quartile range, which is IQR = Q3 - Q1, where Q3 is the third quartile and Q1 is the first quartile. Then find these two numbers:a) Q1 - 1.5*IQRb) Q3 + 1.5*IQRAny observation that is below a) or above b) can be considered an outlier.edit: Chadwick, quartiles are considered robust, meaning that they are not highly effected by outliers. This is because it takes location into account, not the values. Let's look at your data set (sorted).2 3 6 9 13 18 21 106position of Q1 = (8+1)/4 = 2.25Q1 = 0.75(3)+0.25(6) = 3.75position of Q2 = (8+1)/2 = 4.5Q2 = (9+13)/2 = 11position of Q3 = 3(8+1)/4 = 6.75Q3 = 0.25(18)+0.75(21) = 20.25Notice that none of these actually use the value 106. Let's continue.So IQR = Q3-Q1 = 20.25-3.75 = 16.5Q1-1.5*IQR = 3.75-1.5*16.5 = -21Q3+1.5*IQR = 20.25+1.5*16.5 = 45No numbers are below -21, but 106 is above 45, so it can be considered an outlier.Hope I helped!! ((:
Can the median of the data set be the same as Q1 and Q3?
Yes. An example: the data set {1, 1, 2, 2, 2, 2, 2, 2, 2, 3, 5} has median = Q1 = Q3 = 2.
