0
Still curious? Ask our experts.
Chat with our AI personalities
Rafa
Coach
SteveAdd your answer:
Earn +20 pts
How does one find if any data points are an outlier on the high end of a distribution?
There is no formal definition of a outlier: it is a data point that is way out of line wit the remaining data set.If Q1 and Q3 are the lower and upper quartiles of the data set, then (Q3 - Q1) is the inter quartile range IQR. A high end outlier is determined by a value which is larger thanQ3 + k*IQR for some positive value k. k = 1.5 is sometimes used.
How does the outlier affect the median of this data?
An outlier is 1.5 times the mean, when you are taking an average it may give an inaccurate representation of the data. It usually does not affect the median.* * * * * The above definition of an outlier is total rubbish! It is necessary to have a measure of the central tendency (mean or median) AND spread (standard deviation or inter quartile range - IQR) to define an outlier.If Q1 and Q3 are the lower and upper quartiles, then outliers are normally defined as observations lying below Q1 - k*IQR or above Q3 + k*IQR. There is no universally agreed definition of outliers and hence no fixed value for k. But k = 1.5 is often used.
How do you find the outlier number?
Find the inter quartile range, which is IQR = Q3 - Q1, where Q3 is the third quartile and Q1 is the first quartile. Then find these two numbers: a) Q1 - 1.5*IQR b) Q3 + 1.5*IQR Any observation that is below a) or above b) can be considered an outlier. Chadwick, quartiles are considered robust, meaning that they are not highly effected by outliers. This is because it takes location into account, not the values. Let's look at your data set (sorted). 2 3 6 9 13 18 21 106 position of Q1 = (8+1)/4 = 2.25 Q1 = 0.75(3)+0.25(6) = 3.75 position of Q2 = (8+1)/2 = 4.5 Q2 = (9+13)/2 = 11 position of Q3 = 3(8+1)/4 = 6.75 Q3 = 0.25(18)+0.75(21) = 20.25 Notice that none of these actually use the value 106. Let's continue. So IQR = Q3-Q1 = 20.25-3.75 = 16.5 Q1-1.5*IQR = 3.75-1.5*16.5 = -21 Q3+1.5*IQR = 20.25+1.5*16.5 = 45 No numbers are below -21, but 106 is above 45, so it can be considered an outlier.
Write the Arden's method to convert an NFA to DFA with expression?
here first we looking on the given diagram and after this we select all the incoming input like in q1 all the input are q1=q2 0+ q1 1 or q2=q3 1 + q2 0 q1 is a state and when q2 sent 0 then its going to q1 so the value add into the q1 ok same in q2...
Procedure for calculating quartile deviation for raw data?
procedure: step 1: arrange your raw data in increasing order. step 2: find the Q1 is the size of the (n+1)/4th value. step 3: find the Q3 is the size of the 3(n+1)/4th value. Quartile Deviation(QD)= (Q3-Q1)/2 for example: 87 ,64,74,13,19,27,60,51,53,29,47 is the given data step 1: 13,19,27,29,47,51,53,60,64,74,87 step 2: (n+1)/4=3 therefore Q1=27 step 3: 3(n+1)/4=9 therefore Q3=6 implies QD=18.5
