As a quadratic expression it is: w^2 +10w +21
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-63=7w
Written out f(w) = w^2 + 7w + 12 there is no particular answer since it depends on what w is equal to. normally this type of question is posited as "Solve for w with f(w) = 0?" or to change its form to (ax + b)(cx + d) if f(w) = w^2 + 7w + 12 and f(w) = 0 then 0 = w^2 + 7w + 12 simply look at the factors of 12 1 x 12 2 x 6 3 x 4 now consider (w + a)(w + b) = w^2 + aw + bw + ab = w^2 + (a+ b)w + ab since you know 3 x 4 = 12 , and 3 + 4 = 7 this give you 0 = (w + 3) (w + 4) or f(w) = (w + 3)(w + 4) solving for zero w = either -3 or -4 as (-3 + 3)(-3 + 4) = (0)(1) = 0 or (-4 + 3)(-4 + 4) = (-1)(0) = 0 so depending on what you are actually looking for the answer is w^2 + 7w +12 = (w + 3)(w + 4) or -3 and -4
"16-7w plus 14-6w" is an algebraic expression - not an equation nor an inequality. It cannot be solved. So there is no way to determine the value of w and therefore the value of w-1.
3w + 4e + 7w - e3 = 10w - e
Ill assume you mean for an are of a rectangle. w will stand for width. So you know the equation for a rectangle is L*W, so if length is 7W, then the area is 7W*W=Area or 7W^2