4x + 3 doesn't factor. It is in its simplest form.
If the question gives 4x-3=9, then we can solve: 4x-3=9 4x=6 x=3/2, or 1.5
Is there an operator missing from this question? * 3 + 4x = 19 => x = 4 * 3 - 4x = 19 => x = -4 * 3 . 4x = 19 => x = 19/12
4x-6 = -2x-3 4x+2x = 6-3 6x = 3 x = 3/6 = 1/2
y = 4x-3
(4x2 - 13x - 12)/(4x+ 3) = (4x + 3)(x - 4)/(4x + 3) = (4x + 3)(x - 4)/(4x + 3) = x - 4 :)
4x + 3 doesn't factor. It is in its simplest form.
4x + 3 cannot equal 4x + 12:4x + 3 = 4x + 12 (given)3 = 12 (subtract 4x from both sides)
(2x - 3)(4x + 9)(2x + 3) = (2x - 3)(2x + 3)(4x + 9) = [(2x)^2 - (3^2)](4x + 9) = (4x^2 - 9)(4x + 9) = (4x^2)(4x) + (4x^2)(9) - (9)(4x) - (9)(9) = 16x^3 + 36 x^2 - 36x - 81
16x² - 24x + 9 factors to (4x - 3)(4x - 3) or (4x - 3)2
5+4x-7 = 4x+3-x 4x-2 = 3x+3 4x-3x = 3+2 x = 5
The cube expression of 4x is (4x)^3, which simplifies to 64x^3.
4x - 3 = 5 4x = 5 + 3 4x = 8 x = 8/4 x = 2
(4x + 3)(4x + 3) (4x + 3)2
4x-3+6x+3 4x+6x=10x -3+3=0 10x is the answer!
If the question gives 4x-3=9, then we can solve: 4x-3=9 4x=6 x=3/2, or 1.5
4x-3-8 = 8 4x = 8+8+3 4x = 19 x = 4 and 3/4