43+n
N+43=6(12) n+43=72 -43 -43 n=29
Add any two numbers that add to 1134 or 7734. So pick any number, say n. Calculate the second number as 1134 - n or 7734 - n. Add these two.
The number halfway between 27 and 43 can be found by taking the average of the two numbers. To calculate this, you add 27 and 43 together, which equals 70, and then divide by 2 to get 35. Therefore, the number halfway between 27 and 43 is 35.
5050 To add all numbers from 1 to n: (n/2)(n + 1), in this case n = 100 so it is 50 x 101...
-43
N+43=6(12) n+43=72 -43 -43 n=29
298930
43
n=43. 2n=86 is the same as saying 2 of what is 86? or 2 x n = 86? (replace "of" with x and "is" with =) REad it like an equation. so, 2x43=86 and n=43
let the number be n, then 37% of n is .37n and add that to the number and you have n+.37n or n(1.37)
n + 24
The answer is 5,950. Note that when adding a number to itself n times, you simply multiply the number by n. In this case, n is 10, so 595 x 10 = 5950.
Add any two numbers that add to 1134 or 7734. So pick any number, say n. Calculate the second number as 1134 - n or 7734 - n. Add these two.
The atomic number is 21: The mass number is the sum of protons and neutrons, while the atomic number is the number of protons, designated n. From the statement of the problem, n+n+3 = 45, or 2n = 42, or n=21.
Let the intgers be n- 1 n , & n+1 . This is consecutive. Hence Adding (n-1) + n + ( n +1) = 126 Add the LHS 3n = 126 Divide both sides by '3' n = 42 Hence n- 1 = 41 & n +1 = 43 So the consecutive integers are 41,42, & 43.
The number halfway between 27 and 43 can be found by taking the average of the two numbers. To calculate this, you add 27 and 43 together, which equals 70, and then divide by 2 to get 35. Therefore, the number halfway between 27 and 43 is 35.
5050 To add all numbers from 1 to n: (n/2)(n + 1), in this case n = 100 so it is 50 x 101...