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Q: What is the answer to add 43 to a number n?

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N+43=6(12) n+43=72 -43 -43 n=29

Add any two numbers that add to 1134 or 7734. So pick any number, say n. Calculate the second number as 1134 - n or 7734 - n. Add these two.

5050 To add all numbers from 1 to n: (n/2)(n + 1), in this case n = 100 so it is 50 x 101...

-43

Designate the unknown number as n. From the problem statement, n/2 + 98 = 100, or n = 4.

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N+43=6(12) n+43=72 -43 -43 n=29

298930

43

The atomic number is 21: The mass number is the sum of protons and neutrons, while the atomic number is the number of protons, designated n. From the statement of the problem, n+n+3 = 45, or 2n = 42, or n=21.

n=43. 2n=86 is the same as saying 2 of what is 86? or 2 x n = 86? (replace "of" with x and "is" with =) REad it like an equation. so, 2x43=86 and n=43

let the number be n, then 37% of n is .37n and add that to the number and you have n+.37n or n(1.37)

n + 24

The answer is 5,950. Note that when adding a number to itself n times, you simply multiply the number by n. In this case, n is 10, so 595 x 10 = 5950.

Add any two numbers that add to 1134 or 7734. So pick any number, say n. Calculate the second number as 1134 - n or 7734 - n. Add these two.

Let the intgers be n- 1 n , & n+1 . This is consecutive. Hence Adding (n-1) + n + ( n +1) = 126 Add the LHS 3n = 126 Divide both sides by '3' n = 42 Hence n- 1 = 41 & n +1 = 43 So the consecutive integers are 41,42, & 43.

5050 To add all numbers from 1 to n: (n/2)(n + 1), in this case n = 100 so it is 50 x 101...

=n^2 +n =n(n+1) since either n or n+1 has to be even (consecutive numbers) the answer always is an even number