Simply:
Divide 999 by 2 = 499.5, then some common sense tells us 499 & 500.
Algebra:
[x] + [x + 1] = 999 {where x = first # & x+1 = the consecutive number}
2x + 1 = 999 {subtract 1 from both sides}
2x = 998
x = 499
& x +1 = 500
Math is magical.
The numbers are 18 and 20.
41, 42, 43
The answer to that question is 6,7,8,9.
224 x 226
For the product to be zero, one of the numbers must be 0. So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.
Assuming the question concerns numbers whose SUM is 192, the answer is 62, 64 and 66.
24,25,26
The numbers are 18 and 20.
The numbers are 272 and 274.
62 & 61
The answer to that question is 6,7,8,9.
They are 16 and 18
41, 42, 43
The numbers are -16 and -15.
10 and 12
224 x 226
26 28 30