To perform the multiplication of (x + 4)(x + 5), you need to use the distributive property. This means you multiply each term in the first parenthesis by each term in the second parenthesis. (x + 4)(x + 5) = xx + x5 + 4x + 45 Simplify this further to get x^2 + 5x + 4x + 20, which simplifies to x^2 + 9x + 20.
x = 14
y + 12 = -3(x - 2) y + 12 = -3x + 6 y = -3x - 6 or y = -3(x + 2)
24 times 14 equals 330
-2(x+4) = -2x-8
2(1 - 3x + 6) = -x 14 - 6x = -x 14 - 6x + 6x = -x + 6x 14 = 5x 14/5 =5x/5 14/5 = x
To perform the multiplication of (x + 4)(x + 5), you need to use the distributive property. This means you multiply each term in the first parenthesis by each term in the second parenthesis. (x + 4)(x + 5) = xx + x5 + 4x + 45 Simplify this further to get x^2 + 5x + 4x + 20, which simplifies to x^2 + 9x + 20.
1,565 = x5 1,5651/5 = (x5)1/5 1,5651/5 = x5/5 1,5651/5 = x 4.3541 = x
(x+8)(x-1)=0 x+8=0 x=-8 x-1=0 x=1 Therefore, the zeroes are -8 and 1.
Assuming that the question is find x in x5=1610; the answer is 4.378901
512 x 5 = 2,560
x10 = x5.x5 = (x5)2 [x power five whole squared] Equation is x10 + x5 - 2 Replacing x10 (x5)2+x5 - 2 Substituting x5 by Y Equation becomes Y2 + Y - 2 = 0 Y2 + 2Y - Y - 2 = 0 Y(Y + 2) - 1(Y+2) = 0 (Y-1)(Y+2) = 0 The values of Y are 1 and -2 Y = x5 = 1 Therefore, x = 1 Y = x5 = -2 x = fifth root of -2, which is an imaginary value.
75 = 3 x 5 x 5
x equals 14
x5 = x3 times x2. In this case x3 = 64 so x = cube root of 64 ie 4
ln(x+14)-lnx=3ln2 ln[(x+14)/x]=ln8 (x+14)/x=8 x+14=8x 14=7x 2=x x=2 Check this answer by plugging x=2 back into the original equation: ln(2+14)-ln(2)=3ln2 ln(16)-ln(2)=3ln2 ln(16/2)=3ln2 ln8=3ln2 3ln2=3ln2 There you go!
What I mean by this equation is: x^3-2x^(x-2.5)+x^(x^x)