Approximately 6,789.98 units2
Perimeter is 300 yards. This is a length and is not measured in square feet which measure area. The area of this in square feet is 150 x 300 ie 45000 sq ft
The perimeter of this two-sided shape is 300+160 = 460 units of length.
The perimeter of a rectangle of dimensions 50 yards x 100 yards is 300 yards.
300+300+450+650 = 1700 metres
300*1800 mm = 540000 mm = 21260 inches approx.This is not the same as 300 mm x 1800 mm which is a measure of an area.
300
Perimeter l+l+w+w= 70ft Area LxW =300 sqft
Perimeter is 300 yards. This is a length and is not measured in square feet which measure area. The area of this in square feet is 150 x 300 ie 45000 sq ft
If you are talking about a rectangle, you can't find the area from just the perimeter. With a perimeter of say 80 units, the sides could be 10 and 30, with an area of 300 square units. But the sides could also be 5 and 35, with an area of 175 square units. There are lots of other possibilities. If you are talking about a square, that's different. Each side is a quarter of the perimeter, so the area is a quarter of the perimeter multiplied by a quarter of the perimeter.
The perimeter of this two-sided shape is 300+160 = 460 units of length.
The smallest possible perimeter is 20-ft, but there is no largest possible perimeter.You can make it as large as you want, with no limit.Examples:5-ft x 5-ft . . . . area = 25 ft2 . . . perimeter = 20 ft2.5-ft x 10-ft . . area = 25 ft2 . . . perimeter = 25 ft1-ft x 25-ft . . . area = 25 ft2 . . . Perimeter = 52 ft6-in x 50-ft . . . area = 25 ft2 . . . Perimeter = 101 ft3-in x 100-ft . . area = 25 ft2 . . . perimeter = 2001/2 ft1-in x 300-ft . . area = 25 ft2 . . . perimeter = 6001/6 ft0.1-in x 3,000-ft . . area = 25 ft2 . . . perimeter = 6,0001/60 ft
Its width works out as 15m and its length 20m and so 15*20 = 300 square m
There is no answer to that question. It depends entirely on the shape of the 300 acres.
Since a square has four sides of equal length, divide the perimeter measurement by four: 300 / 4 = 75 yards.
Presumably 300 is the perimeter if so then let length be x and the width be 20x: 2(length+width) = perimeter 2(x+20x) = 300 2x+40x = 300 42x = 300 x = about 7.142857143 units 20x = about 142.857429 units
Indeterminate from the information given. Maximum is 300 units (1 x 149), minimum would be a circle of area 149 squnits, circumference therefore approx 43¼ units.
The perimeter of a rectangle of dimensions 50 yards x 100 yards is 300 yards.